Question

Which exponential function has an initial value of 2?

Answer 1

Answer:

None of the exponential equations given in the two options have initial value 2.

Step-by-step explanation:

The general form of an exponential function to have initial value of 2 is

$f(x) = 2(b)^{x}$ where b ≠ 1.

Now, in the given two options the first one has equation $f(x) = 3(2)^{x}$, and the other given table forms the exponential function equation $f(x) = \frac{1}{2}(2)^{x}$.

Therefore, none of the exponential equations given in the two options have initial value 2. (Answer)

Answer 2

Answer: f(x) = 2(3x)

Step-by-step explanation: