What is the answer of the equation 2(x+2)-7+x=27

Mathematics

2 answers:

kirza4 [7]3 years ago

5 0

The answer is x = 10

mylen [45]3 years ago

3 0

Answer:

x = 10

Step-by-step explanation:

Solve for x:

2 (x + 2) - 7 + x = 27

2 (x + 2) = 2 x + 4:

2 x + 4 + x - 7 = 27

Grouping like terms, 2 x + x - 7 + 4 = (2 x + x) + (4 - 7):

(2 x + x) + (4 - 7) = 27

2 x + x = 3 x:

3 x + (4 - 7) = 27

4 - 7 = -3:

3 x + -3 = 27

Add 3 to both sides:

3 x + (3 - 3) = 3 + 27

3 - 3 = 0:

3 x = 27 + 3

27 + 3 = 30:

3 x = 30

Divide both sides of 3 x = 30 by 3:

(3 x)/3 = 30/3

3/3 = 1:

x = 30/3

The gcd of 30 and 3 is 3, so 30/3 = (3×10)/(3×1) = 3/3×10 = 10:

Answer: x = 10

You might be interested in

Which equation shows a valid step in solving /2x-6+2x+6=0?

AfilCa [17]

An equation which shows a valid step that can be used to solve the given mathematical equation is $(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3$

<h3>What is an equation?</h3>

An equation simply refers to a mathematical expression that can be used to show the relationship existing between two (2) or more numerical quantities.

In this exercise, you're required to show a valid step which can be used to solve the given mathematical equation. Since both equations are having a cube root, the first step is to take the cube of both sides.

Take the cube of both sides, we have:

$\sqrt[3]{2x - 6} + \sqrt[3]{2x + 6} = 0\\\\(\sqrt[3]{2x - 6})^3 + (\sqrt[3]{2x + 6})^3 = 0^3\\\\(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3$