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alexira [117]
3 years ago
13

Can someone please help me ☹️

Mathematics
1 answer:
Vadim26 [7]3 years ago
7 0

Answer:

When c = 6 and d = 34, there is one solution. When c = 8 and d = 6, there is no solution. When c = 8 and d = 12, there are infinitely many solutions.

Step-by-step explanation:

6x + 34 = 8x +12

-6x          -6x

34 = 2x +12

-12         -12

22 = 2x

11 = x

8x + 6 = 8x +12

-8x        -8x

6 = 12

No solution

8x+12= 8x + 12

-8x-12  -8x - 12

0 = 0

Infinite solutions

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gizmo_the_mogwai [7]

Answer:

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Step-by-step explanation:

The center position can be selected in 3 different ways, the other 4 players can be selected in combinations of 11 players (the center is already selected) taken 4 at a time.

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We have to find, the sides which is opposite, adjacent and hypotenuse here.

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The side adjacent to the given angle 45^o is x. So, here adjacent = x.

The opposite side is opposite to the given angle. So, opposite = 4.

Now we will use SOHCAHTOA that is sin(x) =\frac{Opposite}{Hypotenuse} , cos(x) =\frac{Adjacent}{Hypotenuse} , tan(x) =\frac{Opposite}{Adjacent}, where x is the angle given.

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So we have got the value of x here.

Now to find y, we will use the trigonometric function sine.

sin(45^o) =\frac{4}{y}

we know the value of sin(45^o) =\frac{\sqrt{2}}{2}

By substituting the value we will get,

\frac{\sqrt{2}}{2}  = \frac{4}{y}

By cross multiplying we will get,

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\sqrt{2}y = 8

We will get y by dividing both sides by \sqrt{2}, we will get,

\frac{\sqrt{2}y}{\sqrt{2}}   =\frac{8}{\sqrt{2} }

y =\frac{8}{\sqrt{2}  }

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y =\frac{8\sqrt{2}}{(\sqrt{2})(\sqrt{2})}

y =\frac{8\sqrt{2}}{2}

y = 4\sqrt{2}

So we have got the required values of x and y.

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