What is the conjugate 2x^2 + square root of 3

Solve the following equation for y.

labwork [276]

Answer:

17

Step-by-step explanation:

2y+2=36

Let's solve this equation for 2y first. This means get 2y by itself.

So to get 2y by itself I need to undo that addition of 2 next to it.

The inverse operation of addition is subtraction.

I'm going to subtract 2 on both sides:

2y =36-2

2y =34

Now we want to get y by itself so we divide both sides by 2 since division and multiplication are inverse operations:

y= 34/2

y= 17

3 0

3 years ago

Read 2 more answers

78+22=22+78<br> (16+4)+11=(11+4)+16<br> (12+8)+9=(9+8)+12

Ksju [112]

344444444444444444444444

4 0

3 years ago

How many days would it take a construction loan of $548,048 to earn$50,000 exact interest at 9% interest rate?

san4es73 [151]

$\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\to &50000\\
P=\textit{original amount deposited}\to& \$548048\\
r=rate\to 9\%\to \frac{9}{100}\to &0.09\\
t=years
\end{cases}
\\\\\\
50000=548048\cdot 0.09t\implies \cfrac{50000}{0.09(548048)}=t\implies 1.014\approx t$

8 0

3 years ago

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Write an equation of the line containing the point (3,5) and perpendicular to the line 4x-3y=5

ICE Princess25 [194]

Answer:

Step-by-step explanation:

In order to write the equation of the line perpendicular to the given line, we first have to know what the slope of the given line is, and there's no way to tell by looking at it in its current form, which is standard. We need to solve that equation for y to determine the slope of that line. Solving for y:

$-3y=-4x+5$ and

3y = 4x - 5 (just change all the signs so our y term isn't negative anymore...yes, you're "allowed" to do that!) and

$y=\frac{4}{3}x-\frac{5}{3}$ So we can see now that the slope of this line is 4/3. That means that the perpendicular slope is -3/4. Passing through the given point (3, 5):

$y-5=-\frac{3}{4}(x-3)$ * and

$y-5=-\frac{3}{4}x+\frac{9}{4}$ and

$y=-\frac{3}{4}x+\frac{9}{4}+\frac{20}{4}$ so

$y=-\frac{3}{4}x+\frac{29}{4}$ ** and, in standard form:

4y = -3x + 29 and

3x + 4y = 29***

* : point-slope form

** : slope-intercept form

*** : standard form

3 0

2 years ago

A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$

Replacing we got:

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0

3 years ago