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3 years ago

Help me solve please

Mathematics

2 answers:

Triss [41]3 years ago

4 0

I think The answer is 9.24

ankoles [38]3 years ago

3 0

Answer:

0.10822510822

Step-by-step explanation:

use a calculator

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How many 6 oz servings are in a 1.125-quart pitcher of lemonade? There are servings. Enter an integer or decimal number[more..]

suter [353]

Answer:

Step-by-step explanation:

1 qt = 4 cups

1 cup = 8 fl oz

1.125 qt * (4 cups)/(1 qt) * (8 fl oz)/(1 cup) = 36 fl oz

(36 fl oz)/(6 fl oz) = 6

Answer: 6 servings

5 0

3 years ago

Find the missing value of the direct variation (2,5) (5,y)

Karolina [17]

Answer:

The missing value y=12.5 and we have (5,12.5)

Step-by-step explanation:

The formula used for direct variation is:

$y\: \alpha \:x\\y=kx$

We need to find missing value (2,5)(5,y)

First we will find k, and then y

We have x=2, y=5

Find k:

$y=kx\\5=k(2)\\k=\frac{5}{2}\\k=2.5$

Now, we cam find missing value in (5,y)

We have x=5, k=2.5 and y=?

$y=kx\\y=2.5(5)\\y=12.5$

So, the missing value y=12.5 and we have (5,12.5)

7 0

3 years ago

The expression 6x to the second power gives the surface area of a cube, and the expression x to the third power gives the volume

Furkat [3]

Answer:

Volume = 6 * 6 * 6 = 216 m³

SA = 36 * 6 = 216 m²

Step-by-step explanation:

8 0

3 years ago

I need helppppp pleaseeeeeeeee ,,, i need to know what the words are backwards ,, thank you!

Aliun [14]

Uhh, these give me a headache, I think number 2 is array..

7 0

4 years ago

Read 2 more answers

Please solve these questions for me. i am having a difficult time understanding.

s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

$\angle AED = \angel BEC$ ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

Refer the attached figure

$\angle ABC = 90^{\circ}$

In ΔDBC

BC=DC (Given)

So, $\angle CDB=\angle DBC$ (Opposite angles of equal sides are equal)

So, $\angle CDB=\angle DBC=x$

So, $\angle CDB+\angle DBC+\angle BCD = 180^{\circ}$ (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So, $\angle CDB=\angle DBC=x = 65^{\circ}$

Now,

$\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90$

So, $\angle ABD=90-x=90-65=25^{\circ}$

In ΔABD

AB = BD (Given)

So, $\angle BAD=\angle BDA$ (Opposite angles of equal sides are equal)

So, $\angle BAD=\angle BDA=y$

So, $\angle BAD+\angle BDA+\angle ABD = 180^{\circ}$ (Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

8 0

4 years ago