HELP!!!! If a scale of 2 in:10 ft is used, how long is an object that is 14 in. long

Helpppppppppppppppppp

UNO [17]

Answer:

<em>2 solutions</em>

Step-by-step explanation:

Given the expression

2m/2m+3 - 2m/2m-3 = 1

Find the LCM of the expression at the left hand side:

2m(2m-3)-2m(2m+3)/(2m+3)(2m-3) = 1

open the bracket

4m²-6m-4m²-6m/(4m²-9) = 1

Cross multiply

4m²-6m-4m²-6m = 4m² - 9

-12m = 4m² - 9

4m² - 9+12m = 0

4m² +12m-9 = 0

<em>Since the resulting equation is a quadratic equation, it will have 2 solutions since the degree of the equation is 2</em>

8 0

3 years ago

Is the constant rate increasing or deceasing

nadezda [96]

Increasing most likely

3 0

2 years ago

Read 2 more answers

Find the point(s) of intersection between the quadratic function y = x + 4x + 4 and the linear function y = 2x+4.

Andrews [41]

Answer:

(0, 4)

Step-by-step explanation:

To find the intersection of two lines, we want to find the value when they equal each other. To do this, we want to set the equations equal to each other.

First, let's simplify y = x + 4x + 4 by combining the x's.

y = 5x + 4

Now let's set the equations equal to each other. Since they both equal y, we can set the opposite sides equal to each other.

5x + 4 = 2x + 4

Now you want to combine the terms.

[subtract 4] 5x = 2x

[subtract 2x] 3x = 0

Now you want to isolate the x.

[divide by 3] x = 0

Now we want to find y by plugging x = 0 back into the equations.

y = 5(0) + 4

[multiply] y = 0 + 4

[add] y = 4

Check this with the other equation.

y = 2(0) + 4

[multiply] y = 0 + 4

[add] y = 4

Your answer is correct!

(0, 4)

4 0

2 years ago

Which of the following random variables should be considered continuous? Select one: a. The number of cars owned by a randomly c

kolbaska11 [484]

The Random Variable that should be considered continuous is "The time it takes for a randomly chosen athlete to run 200 meters" , the correct option is (c) .

In the question ,

four random variables are given , we have to select the random variable that is continuous .

A Continuous Random Variable is a random variable X , which can take any value in its domain or in an interval or the union of intervals on the real line is called Continuous random variable .

For Example : weight of middle aged people lying between 40 Kg and 150 Kg .

From the given options ,

the option (c) , the time taken for a randomly chosen athlete to run 200 meters is a interval of time ,

So ,it is can be called as Continuous Random Variable .

Therefore , the option that represents Continuous Random Variable is option(c) .

The given question is incomplete , the complete question is

Which of the following random variables should be considered continuous ? Select one:

(a) The number of cars owned by a randomly chosen adult male

(b) The number of orders received by a mail-order company in a randomly chosen week

(c) The time it takes for a randomly chosen athlete to run 200 meters

(d) The numbers of brothers a randomly chosen person has .

Learn more about Continuous Random Variable here

brainly.com/question/17238189

#SPJ4

3 0

1 year ago

A study of 420,076 cell phone users found that 131 of them developed cancer of the brain or nervous system. Prior to this study

Keith_Richards [23]

Answer:

a) 95% Confidence interval = (0.026%, 0.037%) to 3 d.p

b) The result of the 95% confidence interval does not agree with the previous rate of such cancer because the value 0.0224% does not lie within this confidence interval obtained.

Step-by-step explanation:

Confidence Interval for the population proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample proportion) ± (Margin of error)

Sample proportion = (131/420076) = 0.0003118483 = 0.0312%

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error)

Critical value at 95% confidence interval for sample size of 420,076 is obtained from the z-tables because the sample size is large enough for the properties of the sample to approximate the population properties.

Critical value = 1.960 (from the z-tables)

Standard error = σₓ = √[p(1-p)/n]

n = sample size = 420,076

σₓ = √(0.0003118×0.999688/420076) = 0.0000272421 = 0.0000272

95% Confidence Interval = (Sample proportion) ± [(Critical value) × (standard Error)]

CI = 0.000312 ± (1.96 × 0.0000272)

CI = 0.000312 ± 0.0000534

95% CI = (0.0002586055, 0.0003653945)

95% Confidence interval = (0.000259, 0.000365)

95% Confidence interval = (0.0259%, 0.0365%) = (0.026%, 0.037%) to 3 d.p

b) The result of the 95% confidence interval does not agree with the previous rate of such cancer because the value 0.0224% does not lie within this confidence interval obtained.

Hope this Helps!!!

7 0

3 years ago