ABF= 28 degrees
BCD= 28  degrees since vertical angle are congruent
ABC= 180 -28 = 152 degrees 
        
                    
             
        
        
        
Answer:
Thus, the two root of the given quadratic equation  is 5.24 and 0.76 .
 is 5.24 and 0.76 .
Step-by-step explanation:
Consider, the given Quadratic equation, 
This can be written as ,  
We have to solve using quadratic formula,
For a given quadratic equation  we can find roots using,
 we can find roots using,
 ...........(1)
  ...........(1)
Where,   is the discriminant.
 is the discriminant.
Here, a = 1 , b = -6 , c = 4
Substitute in (1) , we get,





 and
 and 
We know  (approx)
(approx)
Substitute, we get,
 (approx) and
(approx) and  (approx)
(approx)
 (approx) and
(approx) and  (approx)
(approx)
Thus, the two root of the given quadratic equation  is 5.24 and 0.76 .
 is 5.24 and 0.76 .
 
        
                    
             
        
        
        
Step-by-step explanation:
it filled up half the circle (up to the center point) - if we had a full circle. but a little bit is cut off (below AB).
what we see is that the shaded area is the sum of the area of the triangle AOB and 2 equally sized circle segment areas left and right of AOB.
since we are dealing with a half-circle, we have 180° in total. 120° are taken by AOB, so, that leaves us with 180-120 = 60° for both circle segments (so, one has an angle of 30°).
and 2×30° = 1×60°, so we can calculate the area of one 60° segment instead of two 30° segments. 
AOB is an isoceles triangle (the legs are equally long, and therefore also the 2 side angles are equal).
the area of this triangle AOB is
1/2 × a × b × sin(C) = 1/2 × 3 × 3 × sin(120) =
 = 3.897114317... m²
a circle segment area of 60° is 60/360 = 1/6 of the full circle area (as a full circle = 360°).
so, it's area is
pi×r² × 1/6 = pi×3²/6 = pi×3/2 = 4.71238898... m²
so, the total area of the shaded area is
3.897114317... m² + 4.71238898... m² =
= 8.609503297... m²
 
        
             
        
        
        
The top-left one because 3ba is the same as 3ab