Answer: 24
Step-by-step explanation: 58 = 2z - 10
58 - 10 = 48 = 2z
z = 24
Answer:
a) 
b) 394 thousand = 394,000 people will be following the website in 2016
Step-by-step explanation:
Exponential equation for an amount:
The exponential equation for an amount after t years has the following format:

In which y(0) is the initial value and r is the growth rate, as a decimal.
A social media website had 350,000 followers in 2010. The number y of followers increases by 2% each year.
This means that: 
a. Write an exponential growth function that represents the number of followers t years after 2010
In thousands:


b. How many people will be following the website in 2016?
2016 is 6 years after 2010, so this is y(6).

Rounding to the nearest thousand:
394 thousand = 394,000 people will be following the website in 2016
6<span>√2 is already in it's simplest form as a radical.
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Answer:
2
Step-by-step explanation:
the x and y are being multiplied by 2 e.g. 1 × 2 is 2 and 2 × 2 is 4 so the constant is 2
Answer: SAS
Step-by-step explanation:
The Side Angle Side (SAS) postulates that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then these two triangles are congruent