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Maslowich
3 years ago
15

A byte addressable direct-mapped cache has 1024 blocks/lines, with each block having eight 32-bit words. How many bits are requi

red for block offset, assuming a 32-bit address
Computers and Technology
1 answer:
tino4ka555 [31]3 years ago
8 0

Answer and Explanation:

"The inquiry as presented is not necessarily responsible. A word has been states as 32-bit. We need to ask if the frame is "byte-addressable" (From this we can access to get an 8-bit piece of information) or "text-addressable" (the smallest open lump is 32-bit) or maybe "half-word-addressable" (the tiny bundle of information it could reach to 16-bit).

To understand what the smallest request bit of a position is to let anyone know, you have to remember this.

You operate from base up at that stage. We will agree with the byte-addressable structure. Every reserved square at a certain point contains 8 words * (4 bytes/word) = 32 = 25 bytes, so the counterbalance seems to be 5 bits.

The history in a direct-mapped stored is the squares in reserves (12 bits for this position due to 212 = 4096). at a certain point, as you have seen, the tag is also one of the bits left behind.

As the reserve becomes increasingly cooperative. And a similar size remains. These are lesser bits on the list and more bits on the mark.'

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In order to create strong neural networks (connections) in your brain, you've got to __________ the learning process.
sleet_krkn [62]

Answer:

A. Participate actively in

Explanation:

The brain starts to develop even before a child is born and continues into adulthood. During the first few first years of a child's life, neurons, synapses and axon are multiplied to millions. The child's learning process determines the neural connections to be cut off by pruning. An active connection is retained while inactive neurons, synapses and axons are eliminated.

As the child grows, neural connections are strengthened by active participation in the learning process. But when these connections are left idle, they tend to decay.

8 0
3 years ago
The list below shows the number of text messages that five students sent from
liraira [26]

Answer:

Explanation:dhjyfxdhnjfddhjnvcdfg

3 0
4 years ago
Three ways to increase value of a variable ​
krok68 [10]

Answer:

Three ways to increase the value of variable are given below. To eleborate the answer, I am taking a variable x that need to be increase.

  1. x=x+1
  2. x++
  3. x+=1

Explanation:

There are three ways to increase the value of variable.

1. x= x+1

In this case, each time value of x (variable) is incremented and stored in that variable. This equation increase the value of x by 1 each time. For Example

if x=1

then in first iteration

x= x+1 = 2;

If we want to increase the value of x by more than 1, we can add that value with x, as x+2, x+3 and so on.

2. x++

This will increment the value of x by 1. If we use this equation multiple time in program, each time it will increase 1 in value of x.

3. x+=1

This also works same as equation 1. It will increment 1 in this form and can be changed with 2, 3 and so on.

6 0
4 years ago
3. (20 points) Write a C++ recursive function that finds the maximum value in an array (or vector) of integers without using any
Luden [163]

Answer:

Following are the code to this question:

In option (i):

#include <iostream>//defining header file

using namespace std;

int findMax(int B[], int x)//defining recursive method findMax

{

if (x == 1)//defining condition when value of n==1

return B[0];//return array first element

return max(B[x-1], findMax(B, x-1)); // calling recursive method inside max method and return value

}

int main() //defining main method  

{

int B[] = {12, 24, 55, 60, 50, 30, 29};//defining array B

int x= 7;//defining integer variable and assign a value

cout << "Maximum element value of the array is: "<<findMax(B, x)<<endl;//calling method findMax and print value

return 0;

}

Output:

Maximum element value of the array is: 60

In option (ii):

\Rightarrow \ T(n) = 1 + T(n-1)\\\Rightarrow  1 + 1 + T(n-2)\\ \Rightarrow  1 + 1 + 1 + ... n \ times \\\Rightarrow  O(n) \\

Explanation:

In the above-given program a recursive method "findMax" is defined, which accepts an array "B" and an integer variable "n" in its parameter, inside the method a conditional statement is used that, checks value of x equal to 1.

  • If the above condition is true it will return the first element of the array and find the max number.
  • Inside the main method, an array B is declared that assigns some values and an integer variable is declared, that also assigns some values, in the last step print method is used that pass value in method and prints its return value.
  • In the option (ii) we calculate the Big-O notation algorithm value.
5 0
4 years ago
Dana is moving to a new house. She has 15 boxes for books. Each box can hold up to 22 books. Dana has 375 books. How many more b
Snezhnost [94]

Answer:

3

Explanation:

no of boxes 15

each box hold 22 books

then 15×22=330 books occupied

left books are 375-330=45

so 45÷15=3 boxes will be need

3 0
3 years ago
Read 2 more answers
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