They are not congruent because they are the same shape just flipped around
Given:
Vertices of a parallelogram are C(-5,5), D(2,5), E(-1,-1), and H(-8,-1).
P is the intersection point of diagonals CE and DH.
To find:
The coordinates of P.
Solution:
We know that, diagonals of a parallelogram always bisect each other. It means the intersection point of the diagonal is the midpoint point of both diagonals.
We can find the midpoint of either diagonal CE or diagonal DH to get the coordinates of intersection point of diagonals, i.e. P.
So, point P is midpoint of CE. So,





Therefore, the coordinates of point P are (-3,2).
Answer:
what is that
Step-by-step explanation:
<h3>
Answer: C. (x+6) is a factor of p</h3>
Explanation:
p(-6) = 0 means that plugging x = -6 into p(x) leads to p(x) = 0.
If (x+6) was a factor of p(x), then we can say
p(x) = (x+6)q(x)
where q(x) is some other polynomial. Now let's replace x with -6
p(x) = (x+6)q(x)
p(-6) = (-6+6)q(-6)
p(-6) = 0*q(-6)
p(-6) = 0
The value of q(-6) doesn't matter as multiplying 0 with any number leads to 0.
This is all based on the special case of the remainder theorem that says "if p(k) = 0, then (x-k) is a factor of p(x)".