Strategies developed at the departmental level, such as the accounting, human resources, production, and marketing departments,
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Answer:
The probability that 2 or 3 customers will arrive in a 15-minute period is 0.4703
Explanation:
Firstly, we have to determine the segment unit, since the mean is 10 per hour, the segment unit is 1 hour.
The mean(m) = 10
since the period is 15 minutes = 0.25 hour, t= 0.25 hour / 1 hour. Therefore mt= 2*10 = 2.5
The poisson distribution formula P(x) =
Therefore the probability that 2 or 3 customers will arrive in a 15-minute period
P(x=2) or P(x=3) = P(x=2) + P(x=3) = = 0.2565 + 0.2138 = 0.4703
Therefore P(x=2) or P(x=3) = 0.4703
The probability that 2 or 3 customers will arrive in a 15-minute period is 0.4703