Firstly, add 2 to both sides of the equation:
Next, multiply both sides by 5/3:
Next, square root both sides:
Lastly, factor out i (i = √-1) and <u>your answer will be </u>
What is the point of intersection when the system of equations below is graphed on the coordinate plane? -x+y=4 6x+y=-3
2 answers:
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Answer:
- r1 +4×r3 ⇒ r1
- r2 -3×r3 ⇒ r2
Step-by-step explanation:
We note that the coefficient of y in equation (iii) is 1, so it is convenient to use that equation to eliminate y from the others.
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<em>To eliminate the y-variable from equation (i), four times equation (iii) can be added to equation (i).</em>
<em>To eliminate the y-variable from equation (ii), three times equation (iii) can be subtracted from equation (i).</em>
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The result of these operations would be ...
because y^3 is raised to the power of two, we will have to multiply the exponents rather than adding them.
By distributing the power of 2, we will get y^2(6).
Because now the exponents are being multiplied, we can just add them to get y^8. The other y has a power of 1, so we'll just add the power of that y as well to get y^9.
summary:
multiply exponents if they are being raised to a power.
add exponents if they are being multiplied, and only add them if they have the same base (in this case, both the bases of the exponents are y, so we can add them)
