Using disks ...

The volume is 21π units³ ≈ 65.97 units³
The first thing we are going to do for this case is define variables.
We have then:
x: number of days
y: number of pages remaining.
We write the linear equation that models the problem:

The intersection with the vertical axis is:
We evaluate x = 0:

We get the point:

The intersection with the horizontal axis is:
We evaluate y = 0:


We get the point:

Answer:
The graph is:

Graph located in the bottom left.
Answer: 25
Step-by-step explanation: first find x; 60= 10x - 10, then subtract 10 from both sides to get 50, then divide by 5 to get 10, then plug it in to the equation of the side to get 25
Answer:
(a) A = (20mg)/(2^(t/30))
(b) 12.6mg
(c) 129.6years
Step-by-step explanation:
To calculate the amount remaining after a number of half-lives, n, we can make use of:

Where A = amount remaining
B = initial amount

(a) A = (20mg)/(2^(t/30))
(b) Mass after 20years
A = (20mg)/(2^(20/30)) ≈ 12.6mg
(c) After how long will only 1mg remain:
1mg = (20mg)/(2^(t/30))

Taking log of both sides we have:
Log(20) = (t/30)log(2)
t/30 = (log(20))/(log(2)) ≈ 4.3
t/30 = 4.3
t = 30 x 4.3 ≈ 129.6years.
Answer:
Step-by-step explanation:
Discussion
Question One
The first question is just to derive a formula that represents the cost of anything bought in Idaho.
c = p + 6/100 * p
c = p + 0.6 * p
c = 1.06 p
Question Two
The second question requires an entirely different formula. You don't use the first formula. You just use it's idea. Further, you take the sales tax only when you know how much money has exchanged hands.
c = (p - 30/100 p) + 6/100*(p - 30/100 * p)
c = (p - 0.3p) + 0.06* (p - 0.3p)
c = 0.7 p + 0.06*(0.7p) Combine the right side
c = 0.7p + 0.042p Combine
c = 0.742p
33.39 = 0.742p Divide by 0.742
33.39/0,742 = p
p = 45 dollars
The original cost was 45 dollars