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2 years ago

What is the solution for this inequality? 5x< 45 O A. OB. Oc. XS-9

Mathematics

2 answers:

Elodia [21]2 years ago

8 0

Answer:

x < 9

Step-by-step explanation:

Hello!

We solve inequalities the same we would solve equations. What we do to one side we have to do to the other.

5x < 45

Divide both sides by 5

x < 9

The answer is x < 9

Hope this helps!

MariettaO [177]2 years ago

3 0

Answer:

x<9 I hope help you Mark as Brainliest

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Solve for R using cross multiplication

topjm [15]

R/ r+ 15 = 3/8

Cross multiply: top of one side multiplied by bottom of other side:

R x 8 = 3 x r+ 15

Simplify:

8r = 3r + 45

Subtract 3r from both sides:

5r = 45

Divide both sides by 5:

R = 9

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3 years ago

Select the correct answer.

vagabundo [1.1K]

Answer

D. `(y+4) = (5)/(3)(x+ 1)`

Step by step explanation

The given points are (-1, -4) and (2, 1)

Slope = (y2 - y1)/(x2 - x1)

= (1 - (-4)) / (2 - (-1))

= (1 + 4) / (2 +1)

m = 5/3

When two points are given, the equation of the line is

(y - y1) = m (x - x1)

y -(-4) = 5/3 (x - (-1))

y + 4 = 5/3 (x + 1)

The answer is (y+4) = (5)/(3)(x+ 1)

Thank you.

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2 years ago

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3 years ago

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2 years ago

15. A cylindrical glass 10 cm tall and 8 cm in diameter is filled to 1 cm

ANTONII [103]

Answer:

No. The new height of the water is less than the height of the glass(6.33 cm<10 cm)

Step-by-step explanation:

-For the water in the glass to overflow, the volume of the inserted solid must be greater than the volume of the empty space or the ensuing height of water >height of glass.

#Volume of the golf ball:

$V=\frac{4}{3}\pi r^3\\\\=\frac{4}{3}\pi \times 4^3\\\\\approx 268.08\ cm^3$

#The volume of the water in the glass:

$V=\pi r^2 h\\\\=\pi \times 4^2\times 10\\\\\approx 50.27\ cm^2$

We then equate the two volumes to the glass' volume to determine the new height of the water:

$V=\pi r^2h\\\\(206.08+50.27)=\pi r^2 h\\\\h=318.35/(\pi \times 4^2)\\\\=6.33\ cm$

Hence, the glass will not overflow since the new height of the water is less than the height of the glass(6.33 cm<10cm).

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3 years ago