Answer:
c = 8.14 million×(0.9166)^t
4.83 million
Step-by-step explanation:
Data:
t = y - 2007
c₀ = 8.14 million
c₃ = 23 % less than c₁
Part 1. Calculate c₃
c₃ = c₀(1 - 0.23) = 0.77c₀
Part 2. Calculate r
c₃ = c₀r^t
0.77c₀ = c₀r³
0.77 = r³ Divided each side by c₀
r = 0.9166 Took the cube root of each side
The explicit decay model is c = 8.14 million×(0.9166)^t
Part 3. Prediction
t = 2013 - 2007 = 6
c = c₀r^t = 8.14 million×(0.9166)⁶ = 8.14 million × 0.5929 = 4.83 million
The model predicts that there will be 4.83 million cars for sale in 2013.
Answer:
<span>x=<span><span>5±<span>√41</span></span>4</span></span>
Explanation:
<span>2<span>x2</span>−5x+1=3</span>
<span><span>aaaaaaa</span>−3a−3<span>aaa</span></span>Subtract 3 from both sides
<span>2<span>x2</span>−5x−2=0</span>
This equation is not factorable, so use the quadratic formula.
<span>x=<span><span>−b±<span>√<span><span>b2</span>−4ac</span></span></span><span>2a</span></span><span>aaa</span></span> for<span><span>aaa</span>a<span>x2</span>+bx+c=0</span>
<span>a=2,b=−5,c=−2</span>
<span>x=<span><span>−<span>(−5)</span>±<span>√<span><span><span>(−5)</span>2</span>−4<span>(2)</span><span>(−2)</span></span></span></span><span>2⋅2</span></span></span>
<span>x=<span><span><span>5±<span>√41</span></span>4</span></span></span>
hope this helped :)
alisa202
Answer:
Option C
Step-by-step explanation:
We are given a coefficient matrix along and not the solution matrix
Since solution matrix is not given we cannot check for infinity solutions.
But we can check whether coefficient matrix is 0 or not
If coefficient matrix is zero, the system is inconsistent and hence no solution.
Option A)
|A|=![\left[\begin{array}{ccc}4&2&6\\2&1&3\\-2&3&-4\end{array}\right] =0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%262%266%5C%5C2%261%263%5C%5C-2%263%26-4%5Cend%7Barray%7D%5Cright%5D%20%3D0)
since II row is a multiple of I row
Hence no solution or infinite
OPtion B
|B|=![\left[\begin{array}{ccc}2&0&-2\\-7&1&5\\4&-2&0\end{array}\right] \\=2(10)-2(10)=0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%260%26-2%5C%5C-7%261%265%5C%5C4%26-2%260%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D2%2810%29-2%2810%29%3D0)
Hence no solution or infinite
Option C
![\left[\begin{array}{ccc}6&0&-2\\-2&0&6\\1&-2&0\end{array}\right] \\=2(36-2)=68](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%260%26-2%5C%5C-2%260%266%5C%5C1%26-2%260%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D2%2836-2%29%3D68)
Hence there will be a unique solution
Option D
![\left[\begin{array}{ccc}5&10&5\\4&1&4\\-1&-2&-1\end{array}\right] \\=2(10)-2(10)=0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%2610%265%5C%5C4%261%264%5C%5C-1%26-2%26-1%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D2%2810%29-2%2810%29%3D0)
=0
(since I row is -5 times III row)
Hence there will be no or infinite solution
Option C is the correct answer
Answer:
The answer would be 49
Step-by-step explanation:
8(5) + 9
40 + 9
49
Hope this helps! Please mark as Brainliest!
Answer:
c. 250
Step-by-step explanation:
