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eimsori [14]
3 years ago
10

The distance between port M and port N is 162m. A ship left port M with a speed of 45 mph. In 45 minutes another ship left port

N and went towards the first ship with a speed of 36 mph. How long after the departure of the first ship will the two ships meet?
Mathematics
2 answers:
matrenka [14]3 years ago
8 0

Answer:

After 900 minutes

Step-by-step explanation:

when we convert the velocities of the ships into miles/ min we get

45mph=45m/60min=0.75m/min

36mph=36m/60min=0.6m/min

The equations determining the distances  of the ships from the port M (set at x=0) are

D_1=0.75t (for 45mph ship)

D_2=162+0.6(t-45) (for 36mph ship)

The solution to these equation lie at t= 900 minutes; therefore the two ships will meet 900 minutes after the departure of the first ship.

Aneli [31]3 years ago
6 0

Answer:

900 min

Step-by-step explanation:

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Given that:

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<u>Equation of f(l)</u>

The sum of the length and the width is represented as: f(l).

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f(l) = l + w

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See attachment for the graph of f(l)

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This means that:

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Read more about linear equations at:

brainly.com/question/2263981

8 0
3 years ago
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Answer:Ok

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So, I believe it is D

Step-by-step explanation:

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