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eimsori [14]
3 years ago
10

The distance between port M and port N is 162m. A ship left port M with a speed of 45 mph. In 45 minutes another ship left port

N and went towards the first ship with a speed of 36 mph. How long after the departure of the first ship will the two ships meet?
Mathematics
2 answers:
matrenka [14]3 years ago
8 0

Answer:

After 900 minutes

Step-by-step explanation:

when we convert the velocities of the ships into miles/ min we get

45mph=45m/60min=0.75m/min

36mph=36m/60min=0.6m/min

The equations determining the distances  of the ships from the port M (set at x=0) are

D_1=0.75t (for 45mph ship)

D_2=162+0.6(t-45) (for 36mph ship)

The solution to these equation lie at t= 900 minutes; therefore the two ships will meet 900 minutes after the departure of the first ship.

Aneli [31]3 years ago
6 0

Answer:

900 min

Step-by-step explanation:

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swat32
N=1→an=a1 (first term)=16 (on the graph for n=1)→First term = 16
n=2→an=a2 (second term) = 4 (on the graph for n=2)→Second term = 4

ratio=(Second term)/(First term)=a2/a1=4/16
Simplifying the fraction dividing the numerator (4) by 4 and the denominator (16) by 4:
ratio=(4/4)/(16/4)→ratio=1/4

Answer: Option A. First term = 16, ratio = 1/4
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Answer:

I am pretty sure that it is  C

Step-by-step explanation:

A 1,3 so 3 < 3 no not true

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Answer:

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Step-by-step explanation:

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jeyben [28]

Answer:

x = 3; y = -6

Step-by-step explanation:

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---------------------------

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