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Ahat [919]
3 years ago
10

You win a prize and are offered two choices. Which of the choices could be represented by a linear equation?

Mathematics
2 answers:
brilliants [131]3 years ago
6 0

Answer:

choice b because it is constantly going up the same amount.

Sladkaya [172]3 years ago
6 0
It’s Choice b. Yeah :)
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I need help with all the questions plzzz show work and I’ll give u brainliest plzzzzzZzZzZz i need help plzZZz
shusha [124]

Answer:

The answers are given below.

Step-by-step explanation:

7. EFGH is a rectangle. Slope of HE is - \frac {3}{5}

So, the slope of EF is \frac {-1}{- \frac {3}{5}}

                                  = \frac {5}{3}

8 .PQRS is a square.

So, m∠QSR = 45°

[since the diagonals bisect the internal angles of a square]

9. m∠PTQ = 90°

[since the diagonals of a square intersect each other at right angles]

10. RT = 24 unit ,

so,

PR = (2 \times 24) unit

     = 48 unit    [since the diagonals of a square bisect each other]

So, SQ = PR = 48 unit

[since the diagonals of a square are equal]

11. Yes, a squae is a rectangle

12. Since RSTU is a rectangle,

so, ∠RUS + ∠SUT = 90°

⇒3x + 6 + 5x - 4 = 90°

⇒x = 11°

So, ∠RUS = 3x + 6 = 39°

8 0
4 years ago
For f(x)=2x+1 and g(x)=x^2-7, find (f+g)(x)
labwork [276]

For this case we have the following functions:

f (x) = 2x + 1\\g (x) = x ^ 2-7

We must find the following sum of functions:

(f + g) (x)

By definition we have to:

(f + g) (x) = f (x) + g (x)\\(f + g) (x) = 2x + 1 + x ^ 2-7\\(f + g) (x) = x ^ 2 + 2x-6

So, we have to:

(f + g) (x) = x ^ 2 + 2x-6

Answer:

(f + g) (x) = x ^ 2 + 2x-6

3 0
4 years ago
Solve y 3/2 y equal 9​
Evgen [1.6K]

Answer:

6

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the standard form of 5x^2+5y^2-10x+20y-30=0
o-na [289]

5x^2+5y^2-10x+20y-30=0

We need to get the equation in square form

We apply completing the square method

5x^2-10x+5y^2+20y-30=0

Divide all the terms by 5

x^2-2x+y^2+4y-6=0

Group x  terms and y terms separately  

(x^2-2x)+(y^2+4y)-6=0

By completing the square method, we take half of coefficient of x  and square it

\frac{-2}{2} = -1

square it (-1)^2= 1

Add 1 on both sides

(x^2-2x+1)+(y^2+4y)-6=+1

\frac{4}{2} = 2

square it (2)^2= 4

Add 4 on both sides

(x^2-2x+1)+(y^2+4y+4)-6=0+1+4

Add 6 on both sides

(x^2-2x+1)+(y^2+4y+4)=6+1+4

Now factor both parenthesis

(x-1)^2+(y+2)^2=11

The equation of the circle is (x-1)^2+(y+2)^2=11

7 0
4 years ago
Which statement is true? A. 2x – 1 = 13 and x = 6 B. 2x – 1 = 13 and x = 7 C. 2x + 1 = 13 and x = 7 D. 2x – 1 = 13 and x = 11
alexandr1967 [171]

Answer:

B. 2x – 1 = 13 and x = 7

Step-by-step explanation:

We are given 4 equations and a solution for each. We have to tell which of the given solution satisfies the given equation.

Option A.

2x -1 = 13 and x = 6

Using this value in the equation, we get:

2(6) -1 = 13

12 - 1 = 13

11 = 13, which is not true. Hence this option is not valid

Option B.

2x - 1 = 13 and x = 7

Using the value in the equation, we get:

2(7) - 1 =13

14 - 1 =13

13 = 13, which is true. Hence this option is valid.

Option C.

2x + 1 =13 and x = 7

Using the value in the equation, we get:

2(7) + 1 = 13

15 = 13, which is not true. So this option is not valid

Option D.

2x - 1 = 13 and x = 11

Using this value in the equation, we get:

2(11) - 1 = 13

21 = 13, which is not true. Hence this option is not valid.

6 0
3 years ago
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