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3 years ago

10

You win a prize and are offered two choices. Which of the choices could be represented by a linear equation?

2 answers:

brilliants [131]3 years ago

6 0

Answer:

choice b because it is constantly going up the same amount.

Sladkaya [172]3 years ago

6 0

It’s Choice b. Yeah :)

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Cheryl can travel 133.92 miles using 6.2 gallons of gas

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List all the 3-digit numbers that fit these clues .the hundreds digit is greater than7 .the tens is 1 more than the hundreds dig

djverab [1.8K]

In this question, there are 3 conditions that need to be met
1. The number is 3-digit
2. Hundreds digit >7 (number that will fulfill it would be 8 or 9)
3. The tens is 1 more than hundred( since the hundred possibilities is 8 or 9, then 9 in hundreds can't be used since no number higher than 9)
4. The one digit <2( that mean 0, 1)

Using the list above, you can make your possible number:
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3 years ago

Find the distance between the pair of points (-3, 1) and (2, 1)

BARSIC [14]

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Please help with this Math Question...

Nataly [62]

Answer: A

<u>Step-by-step explanation:</u>

f(x) = x³ + 4x² + 7x + 6

possible rational roots are ±{1, 2, 3, 6}

Try x = -2

-2 | 1 4 7 6

<u>| ↓ -2 -4 -6</u>

1 2 3 0 ← remainder is 0 so x = -2 is a root ⇒ (x + 2) = 0

The factored polynomial x² + 2x + 3 = 0 is not factorable so use the quadratic formula to find the roots.

a=1, b=2, c=3

$x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\dfrac{-(2)\pm\sqrt{(2)^2-4(1)(3)} }{2(1)}$

$x=\dfrac{-2\pm\sqrt{4-12} }{2}$

$x=\dfrac{-2\pm\sqrt{-8} }{2}$

$x=\dfrac{-2\pm2i\sqrt{2}}{2}$

$x = -1 \pm i\sqrt{2}$

$x = -1 + i\sqrt{2}$ $x = -1 - i\sqrt{2}$

$x - (-1 + i\sqrt{2})=0$ $x - (-1 - i\sqrt{2})=0$

The factors are:

$(x - 2)[x - (-1 + i\sqrt{2})][x - (-1 - i\sqrt{2})]$

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3 years ago

prohojiy [21]

Where is the other one?

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