3 years ago

If QR is 7 less than twice X, RS is 61 less than 5 times x, and QS is 11 more than x, find X and the measure of each side.

Mathematics

1 answer:

poizon [28]3 years ago

4 0

Answer:

We can't find the answer unless there's the total amount of circumstances.

Step-by-step explanation:

QR= 2x-7

RS= x-61

QS= x+11

2x+7+x-61+x+11

? = 4x-43

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