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Ivahew [28]
3 years ago
13

An investment of P dollars increased to A dollars in t years. If interest was compounded continuously, find the interest rate. (

Round your answer to the nearest whole number.)
A = 4482, P = 1000, t = 25
Mathematics
1 answer:
Gemiola [76]3 years ago
5 0

Answer: the interest rate is 6%

Step-by-step explanation:

The formula for continuously compounded interest is

A = P x e (r x t)

Where

A represents the future value of the investment after t years.

P represents the present value or initial amount invested

r represents the interest rate

t represents the time in years for which the investment was made.

e is the mathematical constant approximated as 2.7183.

From the information given,

A = $4482

P = 1000

t = 25 years

Therefore,

4482 = 1000 x 2.7183^(r x 25)

4482/1000 = 2.7183^25r

4.482 = 2.7183^25r

Taking ln of both sides, it becomes

Ln 4.482 = 25rLn2.7183

1.5 = 25r

r = 1.5/25 = 0.06

r = 0.06 × 100 = 6%

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2 3/4 ÷ 1 7/8=?<br> pls help
Anna11 [10]

Answer:

77/32 or 2 13/32

Step-by-step explanation:

First, convert the mixed numbers into improper fractions, 11/4*7/8

Next, you can just multiply the fractions for your answer!

Hope this helped<3

7 0
2 years ago
Write a quadratic function to model the vertical motion for each​ situation, given ​h(t) equals negative 16t squared plus v0t+h0
Mashcka [7]

Answer:

hmax = 194 ft

The maximum height is 194 ft

Step-by-step explanation:

According to the given equation for the model of the vertical motion. The height at any point in time can be written as;

h(t) = -16t^2 + v0t + h0 .......1

Where;

h(t) = height at time t

t = time

v0 = initial velocity = 96 ft/s

h0 = initial height = 50 ft

To determine the maximum height we need to differentiate the equation 1 to find the time at which it reaches maximum height;

At the highest point/height h' = dh/dt = 0

h'(t) = -32t +v0 = 0

-32t + v0 = 0

t = v0/32

t = 96/32

t = 3 s

At t=3 it is at maximum height.

The maximum height can be derived from equation 1;

Substituting the values of t,v0,h0 into equation 1;

h(t) = -16t^2 + v0t + h0 .......1

hmax = -16(3)^2 + 96(3) + 50 = 194 ft

hmax = 194 ft

The maximum height is 194 ft

5 0
3 years ago
City planners anticipate an 8.2% population growth per year, including new residents and births. The population, in millions of
NNADVOKAT [17]
<h2>Hello!</h2>

The answer is:

The correct option is the third option,

L(p(x))=2.425(1.082)^{x}

<h2>Why?</h2>

From the statement we know the function that models the population growth over the years (p(x)) but we have been told that there is an estimated loss that can be modeled by the function L(p), so in order to find which function represents the final function, we need to composite the function, which is the same that evaluate p(x) into the function L(p).

We are given:

p(x)=2.5(1.082)^{x}

and

L(p(x))=p(0.97)

So, the evaluationg p(x) into L(p), we have:

L(p(x))=p(0.97)\\\\L(p(x))=2.5(1.082)^{x}*(0.97)=0.97*2.5(1.082)^{x} \\\\L(p(x))=0.97*2.5(1.082)^{x}=2.425(1.082)^{x}\\\\L(p(x))=2.425(1.082)^{x}

Hence, the correct option is:

The third option,  

L(p(x))=2.425(1.082)^{x}

Have a nice day!

6 0
3 years ago
Please help with this problem will give brainiest:
lawyer [7]

Answer:

Is there a question?

Step-by-step explanation:

6 0
3 years ago
Write the expression in algebraic form. [hint: sketch a right triangle.] tan(arcsec(x/3))
WARRIOR [948]

Sketch  a right triangle having adjacent side(A) is given as “3”, hypotenuse side (H) is “x” and assigning angle “a” as the angle between A and H. Using Pythagorean theorem, you will get “square root of x-squared minus 9” as the opposite side (O). Using SOH CAH TOA function, and since secant is the reciprocal of cosine, sec(a) = x/3. Thus, a = arcsec(x/3). The remaining expression tan(a) is Opposite side over Adjacent side which is equal to “square root of x^2 - 9” over "3". Therefore, the algebraic expression would be: tan(arcsec(x/3)) = “sqrt (x^2 -9)” /3. Different answers can be made depending on which side you consider the “3” and “x”.

6 0
3 years ago
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