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jolli1 [7]
3 years ago
8

Today, noah swam 1 mile at swim practice and Liam sprinted 880 yards at track practice. How many more yards did Noah travel duri

ng exercise?
Mathematics
1 answer:
Doss [256]3 years ago
6 0
In the given question, there are certain information's that are worth looking at. Firstly Noah swam for a distance of 1 mile at swim practice. Liam on the other hand ran for 880 yards.
Now firstly we need to convert the distance swam by Noah from mile to yards.
We already know that
1 mile = 1760 yard
So Noah swam for a distance of 1760 yards.
On the other hand Liam sprinted for a distance of 880 yards.
So
The distance Noah traveled more than Liam = (1760 - 880) yards
                                                                         = 880 yards
So Noah traveled 880 yards more than Liam.
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4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25
jarptica [38.1K]

Answer with explanation:

\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

 =e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}

Multiplying both sides by Integrating Factor  

x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

6 0
3 years ago
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Step-by-step explanation:

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9=2N

2) Divide both sides of the equation by 2:

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in a certain chemical, the ratio if zinc to copper is 3 to 16. a jar of the chemical contains 320 grams of copper. how many gram
Dennis_Churaev [7]

Answer:

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Step-by-step explanation:

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Let grams of zinc be "x", so we can write the ratios and actual amounts as:

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Then we cross multiply and solve for x, what we want to find out. Shown below:

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There are 60 grams of zinc.

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