Answer:

Step-by-step explanation:
Given △KMN, ABCD is a square where KN=a, MP⊥KN, MP=h.
we have to find the length of AB.
Let the side of square i.e AB is x units.
As ADCB is a square ⇒ ∠CDN=90°⇒∠CDP=90°
⇒ CP||MP||AB
In ΔMNP and ΔCND
∠NCD=∠NMP (∵ corresponding angles)
∠NDC=∠NPM (∵ corresponding angles)
By AA similarity rule, ΔMNP~ΔCND
Also, ΔKAP~ΔKPM by similarity rule as above.
Hence, corresponding sides are in proportion



Adding above two, we get

⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
(2X-3)(4-3X)
=8X-6X²-12+9X
=-6X²+17X-12
That's your answer.
Answer:
Segment U T is congruent to segment X V
Segment S T is congruent to segment W V
Angle V is congruent to angle T