All categories

2 years ago

Identify each line or segment that intersects ⊙ S.

Mathematics

2 answers:

Delicious77 [7]2 years ago

7 0

Answer:

AC, CE, AB, and AS

I belive those are your answers

babymother [125]2 years ago

3 0

Answer:

chords: CE and AB; secant: CE; tangent:t; diameter AB; radii: AS and SB

Step-by-step explanation:

You might be interested in

Just b I need to know, I need explanation also.

Nastasia [14]

Answer:

$\implies \: 2.6851 \text{ \: ft}$

$\\$

Step-by-step explanation:

$\boxed{\boxed{ \blue\bigstar \red{ \bold{ \: \: math \: \: }} \blue\bigstar}}$

$\pink{\implies = \sqrt{ {36.1}^{2} - {36}^{2}} }$

$\orange{ \implies = \sqrt{1303.21} - 1.296}$

$\green{ \implies = \sqrt{7.21} }$

$\red{ \implies = 2.6851 \: \text{ft}}$

4 0

3 years ago

2(x+11) = -26 show all work pls

Degger [83]

Answer:

x = -24

Step-by-step explanation:

First, distribute 2 to all terms within the parenthesis:

2(x + 11) =

2 * x = 2x

2 * 11 = 22

2x + 22 = -26

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS. PEMDAS is the order of operations, and stands for:

Parenthesis

Exponents (& Roots)

Multiplications

Divisions

Additions

Subtractions

First, subtract 22 from both sides of the equation:

2x + 22 (-22) = -26 (-22)

2x = -26 - 22

2x = -48

Next, divide 2 from both sides of the equation:

(2x)/2 = (-48)/2

x = -48/2

x = -24

x = -24 is your answer.

4 0

2 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :