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antoniya [11.8K]

3 years ago

6

Suppose a struggling student who is currently taking pre-statistics and not passing (60%) wants to predict his introductory stat

istics course grade. Should the regression line be use to make this prediction?

1 answer:

ss7ja [257]3 years ago

7 0

Answer:

No

Step-by-step explanation:

Because the model was developed using only pre-statistics course grades between 70% and 95% so it is risky to assume that linear trend will continue far beyond that span of values.

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Kipish [7]

The answer would be 15

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3 years ago

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Using the order of operations, which operation in the given expression should we complete first? 3 6 X 5 - 3 = 3 OA) Multiply 6

eduard

A. Multiple 6 and 5

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Will give brainliest. The volume of a sphere is 36,000 units What is the radius of the sphere?

oksian1 [2.3K]

Answer:

20.48 is the radius of sphere

Step-by-step explanation:

V=(4 /3)πr3

Using the formula

r=(3V /4π)⅓

Solving for "r"

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4 0

2 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

2 years ago

7. Diana took 2 hours to cycle from town X to town Y. Her average speed was 10 kilometers per

motikmotik

Answer:

a.) 20 kilometers

b.)1.67 hours

Step-by-step explanation:

a.) formula= speed =distance/time

Speed= 10km/hr

Distance=unknown

Time=2hrs

Therefore from formula, distance=speed x time

10 x 2

20 kilometers

b.) If average speed is increased by 2km/hr then

total speed= 2+10=12km/hr

Distance remains constant therefore distance= 20km

Therefore time =distance/speed

20/12

= 1.67 hours

7 0

3 years ago