Firstly, I noticed that there are fractions, decimals, and percents. I will change everything to percents, so it’s more easy for me to compare each of them.
List 1. 140%, 25%, 14%. This is from greatest to least, not least to greatest.
List 2. 25%, 14%, 14%. This is not from least to greatest, either.
List 3. 14%, 25%, 140%. This is from least to greatest.
List 4. 140%, 14%, 25%. This is not from least to greatest.
List 3 is from least to greatest. I got this answer by converting all of the fractions and decimals to percentages.
Whats the normal arm span for these heights? : 4'10,4'11,5'0,5'4,5'5,5,'7,5'8,5'9,5'10,5'11,6'0
Svetllana [295]
In adults, the arm span is approximately 5 cm greater than the height in adult males and 1.2 cm in
adult females. To calculate the arm span for the heights given, we add
5cm to their height. The following are the results:
Height Arm Span Length (in cm)
4’10 152.32
4’11 154.86
5’0 157.4
5’4 167.56
5’5 170.10
5’7 175.18
5’8 177.72
5’9 180.26
5’10 182.80
5’11 185.34
6’0 187.88
To add, the total measurement of the length from the furthermost
part of an individual's arms to the other end
when raised equidistant to the ground at shoulder height at a 90º angle
is called the arm span or wingspan.
Answer: Mary need to make at-least 95 on her fourth test to earn an A in her algebra course.
Step-by-step explanation:
Let x be the grades scored by Mary in the fourth algebra test.
Mary has grades of 95, 82, 88 on her first three algebra tests.
Then, the combined scores in four test will become = 95+82+88+x = 265+x
Average score = (Sum of all scores) ÷ (Number of tests)
As per given ,
To earn an A in an algebra course, a student must have a test average of at least 90.
i.e. Average score ≥ 90
Hence, Mary need to make at-least 95 on her fourth test to earn an A in her algebra course.
Hello from MrBillDoesMath!
Answer:
1^3 = 1
2^3 = 8
3^3 = 27
4^3 = 64
5^3 = 125
6^3 = 216
7^3 = 343
8^3 = 512
9^3 = 729
10^3 = 1000
Thank you,
MrB
Answer:
1. G
2. Not sure what you are ask
