When we factor out something, we divide the factor by the equation. For example if we were to factor 3 out of 6, It will be 3(2). We got this answer by dividing 3 and 6. Using this concept:
![\frac{-1}{4}[( \frac{-1}{2} / \frac{-1}{4}) - ( \frac{5}{4} y / \frac{-1}{4})]](https://tex.z-dn.net/?f=%20%5Cfrac%7B-1%7D%7B4%7D%5B%28%20%5Cfrac%7B-1%7D%7B2%7D%20%2F%20%5Cfrac%7B-1%7D%7B4%7D%29%20-%20%28%20%5Cfrac%7B5%7D%7B4%7D%20y%20%2F%20%20%5Cfrac%7B-1%7D%7B4%7D%29%5D%20%20)
Simplifying:

Hope this helps!
Answer:
49x^2 - 9 = 0As there is no x term, we can pretty much guess we have a situation where we factlrise by something known aa difference of two squares, so to factorise it:49 = 7^29 = 3^2x^2 = (x)^2so...(7x - 3)(7x + 3) = 07x - 3 = 0 7x + 3 = 0x = 3/7 x = -3/7
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24
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