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ryzh [129]
3 years ago
5

The perimeter of the triangle below is 99 units. Find the length of side WX.

Mathematics
1 answer:
frez [133]3 years ago
8 0

Answer:

14

Step-by-step explanation:

Perimeter= 99

XV+VW+WX=99

4z+3z+1+z+2=99

8z+3=99

8z= 96

z=96/8

z= 12

WX= z+2= 12+2= 14.

Hope it helps :-)

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Albania is an Eastern European country that uses a currency called the Albanian Lek (ALL). Right now, $1 (1 USD) exchanges for 1
rosijanka [135]

Answer:

$9398.50

Step-by-step explanation:

Given

\$1 = 106.40\ ALL

Required

Equivalent of 1,000,000 ALL

We have:

\$1 = 106.40\ ALL

and

\$x = 1000000\ ALL

Cross Multiply

x * 106.40 = 1 * 1000000

106.40x = 1000000

Solve for x

x = 1000000/106.4

<em></em>x = \$9398.50<em> -- Approximated</em>

4 0
4 years ago
Simplify ( √ 5)(^3 √ 5) the answer will be a wholenumber and a fraction
arlik [135]

Answer:

\sqrt{5}\cdot\sqrt[3]{5} =\sqrt[6]{5^3} \cdot\sqrt[6]{5^2} =\sqrt[6]{5^5} =5^{(5/6)}

Step-by-step explanation:

The rules of exponents apply, even when they are fractional exponents:

a^b\cdot a^c=a^{b+c}\\\\\sqrt[b]{x^a}=x^{(a/b)}

6 0
4 years ago
The function f(x) = x2 + 6x + 3 is transformed such that g(x) = f(x − 2). Find the vertex of g(x).
garri49 [273]

Answer:

(-1,-6)

Step-by-step explanation:

f(x)=x^2+6x+3

g(x)=f(x-2)

g(x)=(x-2)^2+6(x-2)+3  (Replaced x in f with (x-2))

g(x)=x^2-4x+4+6x-12+3 (Used (x+b)^2=x^2+2bx+b^2 and distributive property)

g(x)=x^2-4x+6x+4-12+3 (Gathered like terms)

g(x)=x^2+2x-5  (Simplified)

The vertex of a parabola occurs at (\frac{-b}{2a},g(\frac{-b}{2a}).

Let's find \frac{-b}{2a} first.

\frac{-2}{2(1)}=-1

Now we can obtain g(\frac{-b}{2a}) which is g(-1) in this case:

g(x)=x^2+2x-5

g(-1)=(-1)^2+2(-1)-5

g(-1)=1-2-5

g(-1)=-1-5

g(-1)=-6.

The vertex is (-1,-6).

6 0
3 years ago
Simplify.<br><br> 8 · 3 · x<br><br> 13x<br> 24x<br> 22x<br> 48x
Elina [12.6K]

8\cdot3\cdot x=(8\cdot3)x=24x

7 0
3 years ago
What are the solutions of x² + 6x - 6 = 10?
Likurg_2 [28]

Answer: x=- 8 or x=2


Step-by-step explanation:

1. To solve this problem you can applly the quadratic formula, which is shown below:

x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}

2. The quadratic  equation is:

x^{2}+6x-6-10=0\\x^{2}+6x-16=0

3. Then:

a=1

b=6

c=-16

4. Therefore, when you substitute these values into the quadratic formula, you obtain the following result:

x=\frac{6+/-\sqrt{6^{2}-4(1)(-16)}}{2(1)}

x_1=-8\\x_2=2


4 0
3 years ago
Read 2 more answers
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