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Arte-miy333 [17]
3 years ago
12

Is 2.85 a rational number

Mathematics
2 answers:
lyudmila [28]3 years ago
8 0

Answer:

Yes

Step-by-step explanation:

Because a rational number can be written in the from a/b

and

285 / 100 = 2.85

rjkz [21]3 years ago
6 0

Answer:

yes

Step-by-step explanation:

A rational number can be expressed in the form

\frac{a}{b} , where a and b are integers

2.85 = 2 \frac{85}{100} = \frac{285}{100} ← a rational number

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A survey conducted by the Consumer Reports National Research Center reported, among other things, that women spend an average of
Nookie1986 [14]

Answer:

(a) The probability that a randomly selected woman shop exactly two hours online is 0.217.

(b) The probability that a randomly selected woman shop 4 or more hours online is 0.0338.

(c) The probability that a randomly selected woman shop less than 5 hours online is 0.9922.

Step-by-step explanation:

Let <em>X</em> = time spent per week shopping online.

It is provided that the random variable <em>X</em> follows a Poisson distribution.

The probability function of a Poisson distribution is:

P (X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0,1,2,...

The average time spent per week shopping online is, <em>λ </em>= 1.2.

(a)

Compute the probability that a randomly selected woman shop exactly two hours online over a one-week period as follows:

P (X=2)=\frac{e^{1.2}(1.2)^{2}}{2!} =0.21686\approx0.217

Thus, the probability that a randomly selected woman shop exactly two hours online is 0.217.

(b)

Compute the probability that a randomly selected woman shop 4 or more hours online over a one-week period as follows:

P (X ≥ 4) = 1 - P (X < 4)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

              =1-\frac{e^{1.2}(1.2)^{0}}{0!}-\frac{e^{1.2}(1.2)^{1}}{1!}-\frac{e^{1.2}(1.2)^{2}}{2!}-\frac{e^{1.2}(1.2)^{2}}{3!}\\=1-0.3012-0.3614-0.2169-0.0867\\=0.0338

Thus, the probability that a randomly selected woman shop 4 or more hours online is 0.0338.

(c)

Compute the probability that a randomly selected woman shop less than 5 hours online over a one-week period as follows:

P (X < 5) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

              =\frac{e^{1.2}(1.2)^{0}}{0!}+\frac{e^{1.2}(1.2)^{1}}{1!}+\frac{e^{1.2}(1.2)^{2}}{2!}+\frac{e^{1.2}(1.2)^{3}}{3!}+\frac{e^{1.2}(1.2)^{4}}{4!}\\=0.3012+0.3614+0.2169+0.0867+0.0260\\=0.9922

Thus, the probability that a randomly selected woman shop less than 5 hours online is 0.9922.

8 0
4 years ago
$46 shoes 2.9 tax round to the nearest cent
Cerrena [4.2K]
$46 with 2.9% tax is:

($46 * 0.029) + $46 = $47.334

2.9% is the same as 0.029, since % means divide by 100 (move decimal 2 places to the left).
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5 0
4 years ago
The difference between the third and first quartiles in a data set, representing the middle half of
pav-90 [236]

Answer:

Interquartile range

Step-by-step explanation:

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Interquartile range (IQR) = Q3 - Q1

WHERE ;

Q3 = 3/4 * (n+1)th term and the first quartile (Q1) is given as ;

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Likurg_2 [28]

Answer:

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Step-by-step explanation:

That would be nCr =  n! / (r!)(n-r!).

A quick way of working these out is as follows:

Take 7C4:

this  is  7*6*5*4/4*3*2*1   Cancelling out the 4 and 3*2:

=  7*5

= 35.

15C12 = 15C(15-12)

= 15C3

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=  5*7*13

= 455.

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If ax=a for some number a#0, then x=1
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Answer:

Step-by-step explanation:

ax = a

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