To find a cofunction with the same value as the expression csc 52*, you would use the formula like this. csc (x) = sec (90-x). So if you use csc(52) that equals sec(90-52). This in turn, equals sec(38). So the answer is B.
<u><em>Answer:</em></u>
Nelson burned the most calories per hour
<u><em>Explanation:</em></u>
To solve this question, we will get the amount calories burned by each in one hour and then compare the two values
To do this, we will divide the total amount of calories burned by the total time
<u>1- For Sabra:</u>
We are given that she burnt 845 calories in
(which is equivalent to 3.25) hours
<u>Therefore:</u>
Calories burnt in an hour =
calories/hour
<u>2- For Nelson:</u>
We are given that he burnt 1435 calories in
(which is equivalent to 4.875) hours
<u>Therefore:</u>
Calories burnt in an hour =
calories/hour
<u>3- Comparing the two values:</u>
From the above calculations, <u>we can deduce that</u> Nelson burned the most calories per hour
Hope this helps :)
Answer:
.................................
Step-by-step explanation:
O
2.75
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It's too short.<span> Write at least 20 characters to explain it well.</span>
The fractions which cannbe formed are: 2/3, 3/2, 2/5, 5/2, 3/5 and 5/3.
Now, we find the products with the third number:
2/3*5= 10/3 = 3.33 > 2
3/2*5 = 15 >2= 7.5 > 2
2/5*3= 6/5 (rejected)
5/2*3 = 15/2 > 2
3/5*2= 6/5 (rejected)
5/3*2 = 15/2 = 7.5> 2