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Yuri [45]
2 years ago
11

One fifth of a number added to 6 is 10. find the number

Mathematics
1 answer:
elena-s [515]2 years ago
8 0

Answer:

<h2>20</h2>

Step-by-step explanation:

n/5+6=10

-6

n/5=4

x by 5

n=20

test it

20/5+6=10

4+6=10

10=10

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2 people are packing equal number of small boxes into larger boxes. One person has 3 large boxes that are full of small boxes an
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34 small boxes for each large box.... I just added 24 and 10
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And tell me why they are. or not similar​
WARRIOR [948]
Because of the measurements, no but if you notice closely teh shape looks translated or a reflection
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3 years ago
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Melanie used 864 beads to make 5 bracelets put the .she put the same number of beads on each bracelet. How many beads does each
Yanka [14]

Answer:

172

Step-by-step explanation:

864 / 5 = 172.8

And so there cant' be a half of a bead, so thre is 172.

7 0
3 years ago
Find the surface area of a cylinder with a height of and a base diameter of .
AfilCa [17]

Answer:

207.24 in.

(This is not a rounded answer)

Step-by-step explanation:

So, this will be very fun, simple, and easy!

First thing we do is use this formula, A(s) = 2πrh + 2πr²

We don't know the surface area yet, and that's what we are looking for, so first off we go ahead and plug in the radius, which is 6 divided by 2, and that's 3! The height is 8 inches!

Let's plug in 3.14 for pie too.

A(s) = 2(3.14)3(8) + 2(3.14)3²

Let's start solving.

A(s) = 150.72 + 2(3.14)3²

3 squared is 9!

A(s) = 150.72 + 56.52

A(s) = 207.24 inches

So, the answer is...207.24 in.! THat is the correct answer, but if I'm wrong, please comment so I can change my answer! Thanks for the points, have a great day or else!

3 0
3 years ago
Suppose a triangle has two sides that measure 7 inches and 11 inches. Which of the following could be the length of the third si
Vikki [24]
You need to know the rule or theorem for the lengths of the sides of a triangle,which is: the lengths of any two sides of a triangle must add up to more than the length of the third side.

So, let's examine each option:

<span>A.4 inches => side A: 7, side B: 11, side C: 4 ---> NOT POSSIBLE

Justification:

7 + 4 = 11

11 = 11 => the sum of sides A and C is not greter than the side B, so it does not satisfy the rule.


B. 7 inches => side A: 7, side B: 11, side C: 7. ---> COULD BE

Justification:

7 + 7 = 14; 14 > 11
7 + 11 = 18; 18 > 7


C. 13.5 inches => side A: 7, side B: 11, side C: 13.5: ---> COULD BE

Justification:

7 + 11 = 18; 18 > 13.5
7 + 13.5 = 20.5; 20.5 > 11
11+13.5 = 24.5; 24.5 > 7

D. 18 inches => side A: 7, side B: 11, side C: 18 ---> NOT POSSIBLE

Justification:

7 + 11 = 18; 18 = 18 => it does not satisfy the rule.

E. 20 inches => side A: 7, side B: 11, side C: 20 ---> NOT POSSIBLE

Justification:

7 + 11 = 18; 18 < 20 => it does not satisfy the rule</span>
7 0
4 years ago
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