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3 years ago

Use the following function rule to find f(16.36).

Mathematics

1 answer:

Virty [35]3 years ago

3 0

Plug in 16.36 for x
0.77(16.36)+8.64

Multiply: 12.5972+8.64
Add: 21.2372

answer: 21.2372

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Simplify −2xy + 3x − 2xy + 3x <br><br> A. 4xy +6x B. 2xy C. −4xy + 6x D. 4xy − 6x

marysya [2.9K]

First you must combine like terms, the two terms I this expression are x, and xy. So by adding -2xy to -2xy you get -4xy. Next you must add 3x to 3x. This gives you the simplified expression -4xy+6x. Hope this helps

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3 years ago

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What is this ????><<<<<<<<<<<<<<<

Nat2105 [25]

Answer:

(x, y)

(7, 0)

Bike Trail is at 7, 0... It is 7 spots to the right (on the x axis) and 0 spots up or down (on the y axis)

Step-by-step explanation:

bike trail is the correct answer :)

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3 years ago

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An individual is planning a trip to a baseball game for 16 people. Of the people planning to go to the baseball game, 8 can go o

Sedaia [141]

Answer: There are 4 people who only go to the game on Saturday.

Step-by-step explanation:

Let the number of people go on Saturday be n(A).

Let the number of people go on Sunday be n(B).

Since we have given that

n(A) = 8

n(B) = 12

n(A∪B) = 16

According to rules, we get that

$n(A)+n(B)-n(A\cap B)=n(A\cup B)\\\\8+12-n(A\cap B)=16\\\\20-n(A\cap B)=16\\\\n(A\cap B)=20-16=4$

So, n(only go on Saturday) = n(only A) = n(A) - n(A∩B) = 8-4 = 4

Hence, there are 4 people who only go to the game on Saturday.

4 0

3 years ago

Describe the rotation of J

Serga [27]

Answer:

The coordinates of J' when rotating by 90° counterclockwise will be: J'(3, 1)

The coordinates of J' when rotating by 90° clockwise will be: J'(-3, -1)

Step-by-step explanation:

Square JKLM with vertices

J(1, -3)

K(5, 0)

L(8, -4)

M(4, -7)

We have to determine the answer for the image J' of the point (1, -3) when we rotate the point by 90° counterclockwise, we need to switch x and y, make y negative.

In other words, the rule to rotate a point by 90° counterclockwise.

P(x, y) → P'(-y, x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(3, 1)

Therefore, the coordinates of J' when rotating by 90° counterclockwise will be: J'(3, 1).

When the point is rotated by 90° clockwise, we need to switch x and y, make x negative.

In other words, the rule to rotate a point by 90° clockwise.

P(x, y) → P'(y, -x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(-3, -1)

Therefore, the coordinates of J' when rotating by 90° clockwise will be: J'(-3, -1)

3 0

3 years ago

Renata has a home loan for $150,000 at 7.5% interest for 30 years and her payment is $987.00 per month (including principal and

Maru [420]

Answer:

Renata has a home loan for $150,000 at 7.5% interest for 30 years and her payment is $987.00 per month.

I have solved this using excel sheet that is attached here.

p = $150000

r = 7.5%

t = $30\times12=360$

EMI = $987

You can see the excel sheet, after first month principle is $ 149,950.50 and after second month it is $149,900.69 .

Download xlsx

4 0

3 years ago