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Svetllana [295]
3 years ago
9

Solve the problem. The systolic blood pressures of the patients at a hospital are normally distributed with a mean of 136mm Hg a

nd a standard deviation of 13.8mm Hg Find the two blood pressures having these properties: the mean is midway between them and 90% of all blood pressures are between them.
Mathematics
1 answer:
shtirl [24]3 years ago
6 0
<span> we know that the 90 percentile in Z-score is ≈ 1.28 then,
=136 ± 1.28(13.8)
=(118.336 , 153.664)
</span>hope it helps
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A school fair ticket costs $8 per adult and $1 per child. On a certain day, the total number of adults (a) and children (c) who
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$88 adults and $12 children
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The answer is 6 just did it
OleMash [197]

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6

Step-by-step explanation:

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Pirate Jack has an equal number of gold and silver coins. If Pirate Jack splits all of his coins into 7 equal piles for his parr
Tcecarenko [31]

Answer:

The least possible number of coins the Pirate has = 81

Step-by-step explanation:

Given:

Pirate Jack has equal number of gold and silver coins.

When the pirate splits the coins into 7 equal piles he has 4 coins left.

When the pirate splits the coins into 11 equal piles he has 4 coins left.

Every pile has at least 1 coin.

To find the least possible number of coins Pirate Jack has.

Solution:

In order to find the least possible number of coins pirate Jack has, we must find the least common multiple of the number of piles the coins are split into.

So, the least common multiple of 7 and 11 can be found by listing the multiples.

7= 7,14,21,28...............,77

11=11,22,33,44,55,66,77

So, we find the least common multiple of 7 and 11 is 77.

Number of coins left = 4

Total number of coins the pirate must have = 77+4 =81

We can check the answer by dividing 81 by 7 and 11. I both cases we get remainder = 4.

So, the least possible number of coins the pirate has = 81

6 0
4 years ago
WORTH 12 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! HELP ASAP
IrinaK [193]

Answer:

\large\boxed{S.A.=1,000\ u^2}

Step-by-step explanation:

We have two congruent right triangles and three rectangles.

First, calculate the length of the hypotenuse using the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have

leg=8,\ leg=15,\ hypotenuse=h

Substitute:

h^2=8^2+15^2\\\\h^2=64+225\\\\h^2=289\to h=\sqrt{289}\\\\h=17

The formula of an area of a right triangle:

A_t=\dfrac{(leg)(leg)}{2}

Substitute:

A_t=\dfrac{(8)(15)}{2}=(4)(15)=60

The formula of an area of a rectangle:

A=wl

w - width

l - length

Rectangle 1:

w = 15, l = 22

A_1=(15)(22)=330

Rectangle 2:

w = 17, l = 22

A_2=(17)(22)=374

Rectangle 3:

w = 8, l = 22

A_3=(8)(22)=176

The Surface Area of the triangular prism:

S.A.=2A_t+A_1+A_2+A_3

Substitute:

S.A.=2(60)+330+374+176=1,000

8 0
3 years ago
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