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satela [25.4K]
4 years ago
6

Which value of g makes 26=7(g-9)+12 a true statement?

Mathematics
1 answer:
KatRina [158]4 years ago
6 0
Choice A




Reasoning

26=7(g-9)+12
26=7(11-9)+12
26=7(2)+12
26=14+12
26=26
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5 for $49.95 or 3 for $34.95?​
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I'd love to help but we need more details

Step-by-step explanation:

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URGENT NEED HELP WITH A MATH QUESTION
irakobra [83]

Answer:

The image of point P is (1 , -1)

Step-by-step explanation:

- If point (x , y) rotated about the origin by angle 90° anti-clock wise

∴ Its image is (-y , x)

- If point (x , y) rotated about the origin by angle 90° clock wise

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∵ P = (-1 , -1)

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∵ x-coordinate of point P = -1

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∵ y-coordinate of point P is -1

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8 0
4 years ago
Evaluate 6 • 3 ÷ start root 9 end root – 1.<br> A. 2<br> B. 3<br> C. 5<br> D. 6
Alborosie

6 * 3 / sqrt9

<em><u>Using PEMDAS, solve SQRT first.</u></em>

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7 0
3 years ago
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A=(-2,-7) B=(-6,4) C=(-2,7) D=(2,4) What is the perimeter?
Nata [24]

 

\displaystyle\bf\\AB=\sqrt{\Big(-6-(-2)\Big)^2+\Big(4-(-7)\Big)^2}\\\\AB=\sqrt{\Big(-6+2\Big)^2+\Big(4+7\Big)^2}\\\\AB=\sqrt{\Big(-4\Big)^2+\Big(11\Big)^2}\\\\AB=\sqrt{16+121}\\\\\boxed{\bf AB=\sqrt{137}}

.

\displaystyle\bf\\BC=\sqrt{\Big(-2-(-6)\Big)^2+\Big(7-4\Big)^2}\\\\BC=\sqrt{\Big(-2+6\Big)^2+\Big(7-4\Big)^2}\\\\BC=\sqrt{\Big(4\Big)^2+\Big(3\Big)^2}\\\\BC=\sqrt{16+9}\\\\BC=\sqrt{25}\\\\\boxed{\bf BC=5}

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\displaystyle\bf\\CD=\sqrt{\Big(2-(-2)\Big)^2+\Big(4-7\Big)^2}\\\\CD=\sqrt{\Big(2+2\Big)^2+\Big(4-7\Big)^2}\\\\CD=\sqrt{\Big(4\Big)^2+\Big(-3\Big)^2}\\\\CD=\sqrt{16+9}\\\\CD=\sqrt{25}\\\\\boxed{\bf CD=5}

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\displaystyle\bf\\AD=\sqrt{\Big(2-(-2)\Big)^2+\Big(4-(-7)\Big)^2}\\\\AD=\sqrt{\Big(2+2\Big)^2+\Big(4+7\Big)^2}\\\\AD=\sqrt{\Big(4\Big)^2+\Big(11\Big)^2}\\\\AD=\sqrt{16+121}\\\\\boxed{\bf AD=\sqrt{137}}

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\displaystyle\bf\\P=AB+BC+CD+AD=\sqrt{137}+5+5+\sqrt{137}\\\\\boxed{\bf P=10+2\sqrt{137}}

 

4 0
3 years ago
A is (-2,1)
valkas [14]

1) in order to solve this problem you must to obtain The value of K,  for it you know by definition  that the  horizontal slope  of the side BC  is zero ,

then m = Y2-Y/X2-X1,   0 = 5-K/4-6⇒0 = 5-K⇒K = 5

known this value for K   you ca find the equation of thE line that pass through  A and C

2) Following the same procedure in first place you calculate the slope with the points A(-2,1) Y C ( 4,5)

m= 5-1/4-(-2) = 2

now with any point  A  or C and the slope you obtain the line

A(-2,1)

y-y1 = m (x-x1) ,   Y-1= 2(X-(-2)⇒Y-1= 2X+4⇒Y=2X+4-1⇒Y =2X+3


7 0
3 years ago
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