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3 years ago

Please help....Alinakincsem Ace

Mathematics

1 answer:

TiliK225 [7]3 years ago

3 0

Answer:

The correct answer option is E. [83 + 2(79) + 4(88)] × 1/7.

Step-by-step explanation:

We are given the quiz average, test average and final average for Sabra's grades for a class.

Given that her test average counts twice as much as her quiz average and final exam counts twice as much as her test average for her overall average:

$(83+79+79+88+88+88+88)$ ÷ $7$

This can also be written as:

[83 + 2(79) + 4(88)] × 1/7

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