f(x) = 3x +2
f(2) = 3(2) + 2 = 8
Now
f(x) = (2x -7) / 3
let f(x) = y and f(y) = x;
y = (2x -7) / 3
x = (3y + 7) / 2
So
f(y) = (3y + 7) / 2
this f(y) is the inverse of f(x); hence
f^-1 (x) = (3x + 7) / 2
Now f^-1(3) = (9+7) / 2 = 8
For the third and last part,
2y + 14 = 4y – 2
2y = 16
y = 8
<span>Hence all the three
parts gives the same results.</span>
The factor of
exists
.
<h3>
How to determine the factor of ![$a^{2} b+2 a^{2}+3 b+6$](https://tex.z-dn.net/?f=%24a%5E%7B2%7D%20b%2B2%20a%5E%7B2%7D%2B3%20b%2B6%24)
?</h3>
Let the given factor be ![$a^{2} b+2 a^{2}+3 b+6$](https://tex.z-dn.net/?f=%24a%5E%7B2%7D%20b%2B2%20a%5E%7B2%7D%2B3%20b%2B6%24)
To factor this we use the grouping method
We group the first two terms and last two terms then we factor out the greatest common factor (GCF) from each group.
![$\left(a^{2} b+2 a^{2}\right)+(3 b+6)$$](https://tex.z-dn.net/?f=%24%5Cleft%28a%5E%7B2%7D%20b%2B2%20a%5E%7B2%7D%5Cright%29%2B%283%20b%2B6%29%24%24)
Take out GCF from each group
![$a^{2}(b+2)+3(b+2)$$](https://tex.z-dn.net/?f=%24a%5E%7B2%7D%28b%2B2%29%2B3%28b%2B2%29%24%24)
Now factor out b+2, we get
![$\left(a^{2}+3\right)(b+2)$$](https://tex.z-dn.net/?f=%24%5Cleft%28a%5E%7B2%7D%2B3%5Cright%29%28b%2B2%29%24%24)
The factor of
exists
.
To learn more about the grouping method refer to:
brainly.com/question/24240168
#SPJ4
Answer:
x = 90°
Step-by-step explanation:
Using the identity
cos²x = 1 - sin²x
Given
cos²x - sin x + 1 = 0
1 - sin²x - sin x + 1 = 0
- sin²x - sin x + 2 = 0 ← quadratic equation in sin x ( multiply through by - 1 )
sin²x + sin x - 2 = 0 ← in standard form
(sinx + 2)(sinx - 1) = 0 ← in factored form
Equate each factor to zero and solve for x
sinx + 2 = 0 ⇒ sinx = - 2 ← has no solution as - 1 ≤ x ≤ 1
sinx - 1 = 0 ⇒ sinx = 1 ⇒ x = 90°
solution is x = 90°
Use SOHCAHTOA
Answer is A). 24/25
Answer:
v = m/D
Step-by-step explanation:
Step 1: Write equation
D = m/v
Step 2: Multiply both sides by v
Dv = m
Step 3: Divide both sides by D
v = m/D