All categories

2 years ago

3a + 10 − 4q + 7a − 4q − 6.

Mathematics

2 answers:

soldi70 [24.7K]2 years ago

7 0

Answer:

Step-by-step explanation:

3a+10-4q+7a-4q-6 combine terms

10a-8q+4

Kobotan [32]2 years ago

6 0

Answer:

10a - 8q + 4

General Formulas and Concepts:

Alg I

Combining like terms

Step-by-step explanation:

Step 1: Define expression

3a + 10 - 4q + 7a - 4q - 6

Step 2: Simplify

Combine like terms (a): 10a + 10 - 4q - 4q - 6
Combine like terms (q): 10a - 8q + 10 - 6
Combine like terms: 10a - 8q + 4

You might be interested in

The circumference of a circle can be found using the

hichkok12 [17]

Answer:

It is the second one

Step-by-step explanation:

1st option does not include the number 2 from the equation above,

and 3 and 4, you do not have to divide anywhere in the equation, so those are no possibly correct.

6 0

3 years ago

Another one about right triangles :/

Ad libitum [116K]

Answer:

$\sqrt{1549}$

Step-by-step explanation:

square 18 and square 35 then add together

4 0

2 years ago

Read 2 more answers

Can yall help me I want 3 problems done thank you if not can you at least do one?

Stells [14]

Answer:

1. the plants grew 50%

2. if the plants grew to be 8 inches instead of 9 the they would have grown 33% which is less than 50%

3. 100% increase

Step-by-step explanation:

See image for steps

7 0

2 years ago

PLS SOMEONE HELP ME

Anarel [89]

A and D are 85 degrees

4 0

2 years ago

Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)

Yakvenalex [24]

Answer:

$\sin d = \frac{4}{7}$ ; $\sin e = \frac{\sqrt{33} }{7}$

$\cos d = \frac{\sqrt{33} }{7}$ ; $\cos e = \frac{4}{7}$

$\tan d = \frac{4}{\sqrt{33} }$ ; $\tan e = \frac{\sqrt{33} }{4}$

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

$\sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}$

$\cos \alpha = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}$

$\tan \alpha = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }$

__________________________________________________

According to the question ,

1) When α (alpha) = d

$\sin d = \frac{4}{7}$

$\cos d = \frac{\sqrt{33} }{7}$

$\tan d = \frac{4}{\sqrt{33} }$

2) When α (alpha) = e

$\sin e = \frac{\sqrt{33} }{7}$

$\cos e = \frac{4}{7}$

$\tan e = \frac{\sqrt{33} }{4}$

3 0

2 years ago