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sergiy2304 [10]
3 years ago
5

T/8 = -4 find the value of t please :)

Mathematics
1 answer:
Anna [14]3 years ago
5 0

Answer:

t = -32

Step-by-step explanation:

I multiplied -4 to 8

Have a wonderful day <33

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You charge customers $18.75 for lube service, parts, and labor. Assuming you take one hour's labor at $15, and the parts cost $3
hram777 [196]
Let
T---------> <span>the tax rate on the parts in $

we know that
$18.75=$15+$3.50+$T
T=18.75-15-3.5
T=$0.25
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$0.25--------> x
x=0.25*100/3.50------> x=7.14%------> x=7.1%

the answer is
7.1%</span>
5 0
3 years ago
Ms. Thomas is taking her friends to see a comedy show. The parking fee was $ 35 and the cost of each ticket for the show was $ 4
pychu [463]

1. An expression that will represent the amount of money that Ms. Thomas will spend is <u>p + 45n - c.</u>

2. The amount of money that Ms. Thomas will spend on the comedy tickets for herself and her 2 friends is <u>$155</u>.

<h3>What is a mathematical expression?</h3>

A mathematical expression is a statement that involves two or more variables that require some mathematical operations.

Most commonly, a mathematical expression contains numbers, variables, and operators, which show a value after the mathematical operations.

<h3>Data and Calculations:</h3>

Parking fee = $35

Ticket fee per person = $45

The number of people on the show = 3 (Ms. Thomas and her two friends)

Coupon = $15

Amount of money spent = p + 45n - c

where p = parking fee, n = number of visitors, and c = coupon received.

= 35 + 45 x 3 - 15

= $155

Learn more about mathematical expressions at brainly.com/question/1852123

#SPJ1

3 0
2 years ago
9.4 The heights of a random sample of 50 college stu- dents showed a mean of 174.5 centimeters and a stan- dard deviation of 6.9
gladu [14]

Answer:  a) (176.76,172.24), b) 0.976.

Step-by-step explanation:

Since we have given that

Mean height  = 174.5 cm

Standard deviation = 6.9 cm

n = 50

we need to find the 98% confidence interval.

So, z = 2.326

(a) Construct a 98% confidence interval for the mean height of all college students.

x\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=(174.5\pm 2.326\times \dfrac{6.9}{\sqrt{50}})\\\\=(174.5+2.26,174.5-2.26)\\\\=(176.76,172.24)

(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 174.5 centime- ters?

Error would be

\dfrac{\sigma}{\sqrt{n}}\\\\=\dfrac{6.9}{\sqrt{50}}\\\\=0.976

Hence, a) (176.76,172.24), b) 0.976.

8 0
3 years ago
Coffee company wants to make sure that their coffee is being served at the right temperature. If it is too hot, the customers co
andrey2020 [161]

Answer:

The average temperature of coffee in the sample, which is 70.2.

Step-by-step explanation:

The population is all the costumers. The company has determined that they want the average coffee temperature to be 65 degrees C. So, 65 degrees C is the average of the population.

The sample is the 20 orders. The mean \mu of the sample is 70.2C(That is, the mean of the 20 orders0. So, the correct answer is:

The average temperature of coffee in the sample, which is 70.2.

3 0
3 years ago
If the length of a rectangle is increased by 120 %, and its width is decreased by 20%,
Dima020 [189]
Let length of rectangle=x and width be y
.`. area=x*y
now new length=x+12x/10=22x/10
width=y-y/5=4y/5
now .....
new area=new length-new width=22x/10*4y/5
new area=88xy/50
7 0
4 years ago
Read 2 more answers
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