Cuando has simplificado la ecuación lo mas posible y las expresiones de los dos lados quedan iguales, hay soluciones infinitas. Pero, dado que lo has simplificado y son diferentes, no hay solución.
1.) 7x = 12 + 7x - 12
=> 7x = 7x => infinita solución
2.) x - 11 = 11 + x
=> x = 22 + x => no solución
3.) 2(4x - 6) = 8(x + 2)
=> 8x - 12 = 8x + 16 => 8x = 8x + 28 => no solución
4.) 2x - 9 = 2x - 9
=> infinita solución
5.) 8 + 4x = 4x + 10
=> 4x = 4x - 2 => no solución
Answer: 5/6
Step-by-step explanation:
Use slope formula of y2-y1/x2-x1. So here it doesn’t matter which is which so I did (6,5) x1 and y1 and (0,0) x2 and y2
So plugging it in it would be 0-5/0-6 = -5/-6 which simplifies to 5/6
Let's actually find the roots, using the quadratic formula:
<span>p(x)=x^2+x+3 gives us a=1, b=1 and c=3.
-1 plus or minus sqrt(1^2-4(1)(3))
Then x = -----------------------------------------------
2
The discriminant here is negative, so the roots x will be complex:
-1 plus or minus sqrt(-11) -1 plus or minus i*sqrt(11)
x = ---------------------------------- = -------------------------------------
2 2
These are irrational roots; they cannot be expressed as the ratios of integers.</span>
