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Romashka-Z-Leto [24]
3 years ago
7

2 - The length of a field, 1.2 km long is represented on a map bye

Mathematics
1 answer:
Lostsunrise [7]3 years ago
3 0

Answer:

<h2>1,000,000 mm:1 km</h2>

Step-by-step explanation:

This problem bothers on the conversion of units

to get the scale we need to know how many millimetres are there in one km.

Hence the scale is 1,000,000 mm:1 km

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No files just type it in please and thank you&lt;3
damaskus [11]

Answer:

Option C is correct

Step-by-step explanation:

8 + 8 + 8 + 8 + 8 + 8 = 48

6 \times 8 = 48

<h3>Hope it is helpful...</h3>
6 0
3 years ago
Tylond puts $5,000 into a savings account that earns 4%
MariettaO [177]

Answer:

125,000

Step-by-step explanation:

7 0
3 years ago
ANSWER QUICK AND EXPLAIN HOW TO SOLVE
blsea [12.9K]
\cfrac{a}{sinA}= \cfrac{b}{sinB} \ \ \to \\ sinB= \cfrac{b*sinA}{a} = \cfrac{14*sin35^o}{12}= 0.6692 \ \ \to \ m \angle B=42^o \\ \\ \\ m \angle C=180- m \angle A- m \angle B=180-35-42=103^o \\ \\ \\ \cfrac{a}{sinA}= \cfrac{c}{sinC} \ \ \to \ c= \cfrac{a*sinC}{sinA}= \cfrac{12*sin103^o}{sin35^o} \approx 20.4
6 0
3 years ago
Simplify (x + 2/ x^2 + 2x -3) / (x + 2/x^2 - x)
rjkz [21]

Answer:

The simplest form is x/(x + 3)

Step-by-step explanation:

* To simplify the rational Expression lets revise the factorization

  of the quadratic expression

*  To factor a quadratic in the form x² ± bx ± c:

- First look at the c term  

# If the c term is a positive number, and its factors are r and s they

  will have the same sign and their sum is b.

#  If the c term is a negative number, then either r or s will be negative

   but not both and their difference is b.

- Second look at the b term.  

# If the c term is positive and the b term is positive, then both r and

  s are positive.  

Ex: x² + 5x + 6 = (x + 3)(x + 2)  

# If the c term is positive and the b term is negative, then both r and s

  are negative.  

Ex:  x² - 5x + 6 = (x -3)(x - 2)

# If the c term is negative and the b term is positive, then the factor

  that is positive will have the greater absolute value. That is, if

  |r| > |s|, then r is positive and s is negative.  

Ex: x² + 5x - 6 = (x + 6)(x - 1)

# If the c term is negative and the b term is negative, then the factor

  that is negative will have the greater absolute value. That is, if

  |r| > |s|, then r is negative and s is positive.

Ex: x² - 5x - 6 = (x - 6)(x + 1)

* Now lets solve the problem

- We have two fractions over each other

- Lets simplify the numerator

∵ The numerator is \frac{x+2}{x^{2}+2x-3}

- Factorize its denominator

∵  The denominator = x² + 2x - 3

- The last term is negative then the two brackets have different signs

∵ 3 = 3 × 1

∵ 3 - 1 = 2

∵ The middle term is +ve

∴ -3 = 3 × -1 ⇒ the greatest is +ve

∴ x² + 2x - 3 = (x + 3)(x - 1)

∴ The numerator = \frac{(x+2)}{(x+3)(x-2)}

- Lets simplify the denominator

∵ The denominator is \frac{x+2}{x^{2}-x}

- Factorize its denominator

∵  The denominator = x² - 2x

- Take x as a common factor and divide each term by x

∵ x² ÷ x = x

∵ -x ÷ x = -1

∴ x² - 2x = x(x - 1)

∴ The denominator = \frac{(x+2)}{x(x-1)}

* Now lets write the fraction as a division

∴ The fraction = \frac{x+2}{(x+3)(x-1)} ÷ \frac{x+2}{x(x-1)}

- Change the sign of division and reverse the fraction after it

∴ The fraction = \frac{(x+2)}{(x+3)(x-1)}*\frac{x(x-1)}{(x+2)}

* Now we can cancel the bracket (x + 2) up with same bracket down

 and cancel bracket (x - 1) up with same bracket down

∴ The simplest form = \frac{x}{x+3}

5 0
3 years ago
Read 2 more answers
How can you solve quadratic equation in one variable using factoring method?​
Tresset [83]
Take a quadratic equation in standard form:
If there exists a sum of two numbers that equal b, whose addends produce a product that equals c. You can rewrite the quadratic as a product of two binomials.


For example take
When thought through throughly, -5 had addends, -2 and -3 that produce 6 when multiplied
Thus, we can rewrite the quadratic as.
4 0
3 years ago
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