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Verizon [17]
3 years ago
12

There is a margin of error on a food survey of +/– 5%. What is the range of the number of students who do not want hot dogs if 8

3 of 127 students said they did not want hot dogs on Wednesdays and there are 900 students at the school?
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0
%15 hope this helps. :)
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758% as a decimal to the thousands place is........
fiasKO [112]
7.580 is 758% as a decimal to the thousandths place. 
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3 years ago
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Use the spinner below to find the probability of getting the following number after 1 spin. P(multiple of 3) = (Round to 4 decim
Talja [164]

The value of the probability P(multiple of 3) is 0.3333

<h3>How to determine the probability?</h3>

The spinner that completes the question is added as an attachment

From the attached spinner, we have:

  • Total section = 12
  • Multiples of 3 = 4

The probability is then calculated as:

P(multiple of 3) = Multiples of 3/Total

This gives

P(multiple of 3) = 4/12

Evaluate

P(multiple of 3) = 0.3333

Hence, the value of the probability is 0.3333

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brainly.com/question/25870256

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3 0
2 years ago
In a survey, the planning value for the population proportion is . How large a sample should be taken to provide a confidence in
tatuchka [14]

Answer:

n=350

Step-by-step explanation:

Notation and definitions

n random sample taken  (variable of interest)

\hat p=0.35 estimated proportion  (value assumed)

p true population proportion

Confidence =0.95 or 95% (value assumed)

Me=0.05 (value assumed)

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.586  

And rounded up we have that n=350

4 0
3 years ago
Will 4 5/10 x 6/17 be larger, smaller, the same or impossible to tell than 4 5/10?
Delicious77 [7]
4¹/₂ × ⁶/₁₇
⁹/₂ × ⁶/₁₇
²⁷/₁₇
1¹⁰/₁₇

The product of 4¹/₂ and ⁶/₁₇ will be smaller than 4¹/₂.
3 0
3 years ago
If arc SQ = 84° and ∠RPS = 26°, what is the measure of arc RS? need answer asap thank you
Lera25 [3.4K]

Answer:

arc\ RS=136\°

Step-by-step explanation:

we know that

The measurement of the external angle is the semi-difference of the arcs which comprises

In this problem

m∠RPS=26\° ------> external angle

so

m∠RPS=\frac{1}{2}(arc\ RS-arc\ SQ)

we have

m∠RPS=26\°

arc\ SQ=84\°

substitute the values

26\°=\frac{1}{2}(arc\ RS-84\°)

Solve for arc RS

52\°=(arc\ RS-84\°)

arc\ RS=52\°+84\°=136\°

3 0
3 years ago
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