If arc SQ = 84° and ∠RPS = 26°, what is the measure of arc RS? need answer asap thank you
2 answers:
The angle formed by the intersection of tangent and secant outside the circle equals half the difference of the intercepted arcs ⇒
(arc RS - arc SQ)/2 = <span>∠RPS
(</span>arc RS - 84)/2 = 26
arc RS - 84 = 26 * 2
arc RS - 84 = 52
arc RS = 52 + 84
arc RS = 136°
Answer:
Step-by-step explanation:
we know that
The measurement of the external angle is the semi-difference of the arcs which comprises
In this problem
m∠RPS= ------> external angle
so
m∠RPS=
we have
m∠RPS=
substitute the values
Solve for arc RS
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