The answer to the question is 10
The slope of the handicap ramp is 1/2
The slope of the handicap ramp is gotten from the equation for the slope of a line, m with endpoints (x₁, y₁) and (x₂, y₂).
m = (y₂ - y₁)/(x₂ - x₁)
Since one point of the ramp can be identified by the ordered pair (d, 4d) and another point on the ramp is identified by the ordered pair (3d, 5d), we have that (x₁, y₁) = (d, 4d) and (x₂, y₂) = (3d, 5d).
Substituting the values of the variables into the equation, we have
m = (y₂ - y₁)/(x₂ - x₁)
m = (5d - 4d)/(3d - d)
m = d/2d
m = 1/2
So, the slope of the handicap ramp is 1/2
Learn more about slope of a line here:
brainly.com/question/1617757
Answer:
42
Step-by-step explanation:
x+(x+13)=71
2x+13=71
2x=71-13
2x=58
x=29 (alvin)
71-29=42 (elga)
Answer:
3 1/5+4.5+5 3/10=
16/5+4.5+53/10=
3.2+4.5+5.3=
13
Step-by-step explanation:
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the answer is 400
