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the answer is 1 2 and 3 because they cant be divided by anything
Answer:
The volume of the solid is 
Step-by-step explanation:
In this case, the washer method seems to be easier and thus, it is the one I will use.
Since the rotation is around the y-axis we need to change de dependency of our variables to have
. Thus, our functions with
as independent variable are:
For the washer method, we need to find the area function, which is given by:
![A=\pi\cdot [(\rm{outer\ radius)^2 -(\rm{inner\ radius)^2 ]](https://tex.z-dn.net/?f=A%3D%5Cpi%5Ccdot%20%5B%28%5Crm%7Bouter%5C%20radius%29%5E2%20-%28%5Crm%7Binner%5C%20radius%29%5E2%20%5D)
By taking a look at the plot I attached, one can easily see that for a rotation around the y-axis the outer radius is given by the function
and the inner one by
. Thus, the area function is:
![A(y)=\pi\cdot [(\sqrt{y} )^2-(y^2)^2]\\A(y)=\pi\cdot (y-y^4)](https://tex.z-dn.net/?f=A%28y%29%3D%5Cpi%5Ccdot%20%5B%28%5Csqrt%7By%7D%20%29%5E2-%28y%5E2%29%5E2%5D%5C%5CA%28y%29%3D%5Cpi%5Ccdot%20%28y-y%5E4%29)
Now we just need to integrate. The integration limits are easy to find by just solving the equation
, which has two solutions
and
. These are then, our integration limits.

Answer:
b, the probability that a customer buys a taco, a drink, or both is 45%
Answer:
Kindly check explanation
Step-by-step explanation:
Given the T test output :
T-Test
μ<4.00
t=-3.033077
p=0.002025
x=3.48
Sx=1.150075
n=45
Given that population mean, μ = 6
Confidence level, α = 0.05
The hypothesis :
H0 : μ = 6.00
H1 : μ < 6.00
From the t test output given :
The test statistic :
T = -3.033077
T = - 3.03 (2 decimal places)
The Pvalue :
P = 0.002025
Pvalue = 0.002 (3 decimal places)
The conclusion :
Decision region ; Reject H0 : if Pvalue < α
Since ; Pvalue < α
Reject H0 ; There is sufficient evidence to support claim that sample is from a population with a mean less than 6.