What is the solution to the following system of equations?

Mathematics

2 answers:

seropon [69]4 years ago

7 0

Answer:

X= 2 and Y=1

Step-by-step explanation:

✯Hello✯

↪ So you know what y is so you can substitute into -2x-3y=-7

↪ -20x+33=-7 (thats after you expand the brackets)

↪ -20x=40

↪ this means that x=2. Therefore if u substitute y=1 and its on the options

❤Gianna❤

-Dominant- [34]4 years ago

4 0

Answer:

D. (2,1)

Step-by-step explanation:

Fill in the value for y from the first eq (6x-11) into the second:

-2x - 3(6x-11) = -7

Now simplify:

-2x -18x + 33 = -7

-20x = -7-33

20x = 40

x = 2

Now that we have x, plug it into the top eq to get y:

y = 6*2 - 11 = 1

Et voila, x=2 and y=1, so the solution is (2,1).

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Solve 2x2 + 26 = 0 to identify the roots.

zalisa [80]

Answer:

$x=+/-i\sqrt{13}$

Step-by-step explanation:

To find the roots, factor and set equal to 0 or use the quadratic formula. This quadratic equation does not factor and must be solved using the quadratic formula.

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where a = 2, b=0, and c=26

$x=\frac{0+/-\sqrt{0^2-4(2)(26)} }{2(2)} \\x=\frac{+/-\sqrt{-208)} }{4} \\x=\frac{+/-i\sqrt{16*13)} }{4}\\x=\frac{+/4i\sqrt{13} }{4}\\x=+/-i\sqrt{13}$