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3 years ago

What is the solution to the following system of equations?

Mathematics

2 answers:

seropon [69]3 years ago

7 0

Answer:

X= 2 and Y=1

Step-by-step explanation:

✯Hello✯

↪ So you know what y is so you can substitute into -2x-3y=-7

↪ -20x+33=-7 (thats after you expand the brackets)

↪ -20x=40

↪ this means that x=2. Therefore if u substitute y=1 and its on the options

❤Gianna❤

-Dominant- [34]3 years ago

4 0

Answer:

D. (2,1)

Step-by-step explanation:

Fill in the value for y from the first eq (6x-11) into the second:

-2x - 3(6x-11) = -7

Now simplify:

-2x -18x + 33 = -7

-20x = -7-33

20x = 40

x = 2

Now that we have x, plug it into the top eq to get y:

y = 6*2 - 11 = 1

Et voila, x=2 and y=1, so the solution is (2,1).

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

A triangle is graphed in the coordinate plane. The vertices of the triangle have coordinates (–3, 1), (1, 1), and (1, –2). What

vladimir2022 [97]

Answer:

The perimeter of the triangle is $12\ units$

Step-by-step explanation:

Let

$A(-3,1),B(1,1),C(1,-2)$

we know that

The perimeter of triangle is equal to

$P=AB+BC+AC$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$A(-3,1),B(1,1)$

substitute in the formula

$AB=\sqrt{(1-1)^{2}+(1+3)^{2}}$

$AB=\sqrt{(0)^{2}+(4)^{2}}$

$AB=4\ units$

step 2

Find the distance BC

$B(1,1),C(1,-2)$

substitute in the formula

$BC=\sqrt{(-2-1)^{2}+(1-1)^{2}}$

$BC=\sqrt{(-3)^{2}+(0)^{2}}$

$BC=3\ units$

step 3

Find the distance AC

$A(-3,1),C(1,-2)$

substitute in the formula

$AC=\sqrt{(-2-1)^{2}+(1+3)^{2}}$

$AC=\sqrt{(-3)^{2}+(4)^{2}}$

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step 4

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substitute the values

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6 0

3 years ago

What are the zeroes of f(x) = x2 − 6x + 8? (4 points) x = −4, 2 x = −4, −2 x = 4, 2 x = 4, −2

babymother [125]

Hey there! :)

Answer:

Third option. x = 2, and x = 4.

Step-by-step explanation:

Find the zeros of this quadratic equation by factoring:

f(x) = x² - 6x + 8

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f(x) = (x - 4)(x - 2)

Set each factor equal to 0 to solve for the roots;

x - 4 = 0

x = 4

x - 2 = 0

x = 2

Therefore, the zeros of this equation are at x = 2, and x = 4.

8 0

4 years ago

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