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lawyer [7]
3 years ago
6

On a coordinate plane, a dashed straight line has a negative slope and goes through (0, 3) and (2, negative 1). Everything to th

e left of the line is shaded. Which linear inequality is represented by the graph? y > 2x + 3 y < 2x + 3 y > −2x + 3 y < −2x + 3
Mathematics
2 answers:
stepan [7]3 years ago
8 0

Answer: Last option.

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope of the line and "b" is the y-intercept.

The slope of a line can be found with this formula:

m=\frac{y_2-y_1}{x_2-x_1}

In this case, knowing that this line goes through the points (0,3) and (2,-1), you get that its slope is:

m=\frac{-1-3}{2-0}\\\\m=-2

By definition, a line intersects the y-axis when x=0.

Since the line goes through the point (0,3), you can identify that:

b=3

Then, the equation of this line in Slope-Intercept form, is:

y=-2x+3

You know that everything to the left of the dashed line is shaded, then the symbol of the inequality is .

Therefore, the linear inequality that is represented by the graph is:

y

Juliette [100K]3 years ago
3 0

Answer:

Step-by-step explanation:

The Last one

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4. Celia is making biscuits. Her recipe calls for 1/3 cup of flour, but
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Read 2 more answers
A class survey found that 29 students watched television on Monday, 24 on Tuesday, and 25 on Wednesday. Of those who watched TV
gizmo_the_mogwai [7]

Answer:

There were 49 students in the class

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the students that watched TV on Monday

-The set B represents the student that watched TV on Tuesday.

-The set C represents the students that watched TV on Wednesday.

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a is the number of students that only watched TV on Monday, A \cap B is the number of adults that watched TV both on Monday and Tuesday, A \cap C is the number of students that watched TV both on Monday and Wednesday, and A \cap B \cap C is the number of students that watched TV on every day.

By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following subsets:

a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)

The sums of all of this values is the number of student that were there in the class. This means that we want to find the value of T:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = T

We start finding the values from the intersection of three sets.

Solution:

12 students watched TV on all three days:

A \cap B \cap C = 12

14 students watched TV on both Monday and Tuesday

A \cap B + A \cap B \cap C = 14

A \cap B = 14 - 12

A \cap B = 2

Of those who watched TV on only one of these days, 13 choose Monday, 9 chose Tuesday, and 10 chose Wednesday.

a = 13, b = 9, c = 10

29 students watched television on Monday:

A = 29

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

29 = 13 + 2 + (A \cap C) + 12

A \cap C = 29 - 27

A \cap C = 2

24 on Tuesday

B = 24

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

24 = 9 + (B \cap C) + 2 + 12

B \cap C = 24 - 23

B \cap C = 1

Now we have every value needed to find T:

T = a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)

T = 13 + 9 + 10 + 2 + 2 + 1 + 12

T = 49

There were 49 students in the class

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Greeley [361]

Answer:

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Step-by-step explanation:

there

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