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katrin [286]
3 years ago
12

How do you Simplify fractions

Mathematics
2 answers:
Lilit [14]3 years ago
6 0
By dividing the numbers example i had 3/9 it will divide by 3 FOLLOW ME
Sergio [31]3 years ago
5 0

in order to simplify a fraction you must find a gcf and divide the numerator and denominator by that number. for example:

4/8 has a gcf of 4, so 4 divided by 4 equals 1 and 8 divided by 4 equals  2 so your simplified fraction would be 1/2


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Answer:

47

Step-by-step explanation:

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A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther
mariarad [96]
<h2>Answer:</h2>

<em><u>Recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

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We see that,

a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\

Therefore, on checking, we observe that,

a_{n}=a_{n-1}+(n-1)^{2}

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

<u>At, </u>

<u>n = 1</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0

which is true.

<u>At, </u>

<u>n = 2</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1

Which is also true.

<u>At, </u>

<u>n = 3</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5

Which is true.

<u>At, </u>

<u>n = 4</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14

This is also true at the given value of 'n'.

<em><u>Therefore, the recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

3 0
3 years ago
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ki77a [65]

here's the solution,

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we know,

=》

nth  \: \: term \:  = a   \: + (n - 1) \times d

=》

11th \:  \: term   = 5 + (11 - 1) \times 6

=》

11th \:  \: term = 5 + (10 \times 6)

=》

11th \:  \: term  = 5 + 60

=》

11th \:  \: term = 65

nth term ( 11th term ) = 65

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\tan(\theta) = \dfrac xy

Now,

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5 0
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