4x - 3(x - 2) - x
4x - 3x + 6 - x
4x - 4x + 6
6....u r correct because ur x's cancel out
The greatest common factor (GCF) of 24, 44, and 52 is: 4
Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
Factors of 44: 1, 2, 4, 11, 22
Factors of 52: 1, 2, 4, 13
The common factors between them are 1, 2, and 4, but 4 is the greatest, making it the GCF.
Answer:
27 chickens
Step-by-step explanation:
A chicken farmer also has cows for a total of 30 animals
Both animals have a total of 66 legs
Let a represent the number of chicken
Let b represent the number of cows
a + b= 30........equation 1
Since a chicken has only two legs and a cow has four leg then, the expression can be represented as
2a + 4b= 66........equation 2
From equation 1
a + b= 30
a = 30-b
Substitute 30-b for a in equation 2
2a + 4b= 66
2(30-b) + 4b= 66
60 - 2b + 4b= 66
60 + 2b= 66
2b= 66-60
2b= 6
b= 6/2
b= 3
Substitute 3 for b in equation 1
a + b = 30
a + 3=30
a= 30-3
a= 27
Hence the farmer has 27 chickens
Answer:
The simplest answer would just be 14:19
However the unsimplified answer is 1260:1710
Answer:
a) On average, homes that are on busy streets are worth $3600 less than homes that are not on busy streets.
Step-by-step explanation:
For the same home (x1 is the same), x2 = 1 if it is on a busy street and x2 = 0 if it is not on a busy street. If x2 = 1, the value of 't' decreases by 3.6 when compared to the value of 't' for x2=0. Since 't' is given in thousands of dollars, when a home is on a busy street, its value decreases by 3.6 thousand dollars.
Therefore, the answer is a) On average, homes that are on busy streets are worth $3600 less than homes that are not on busy streets.
