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grigory [225]
3 years ago
11

What is 3 ones and 8 tenths is decimal form

Mathematics
1 answer:
bonufazy [111]3 years ago
5 0
3.8

The 3 is in the one's place, and the 8 is in the tenths place.
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32005008 in word from.
luda_lava [24]
Thirty two million, five thousand and eight
4 0
3 years ago
Number 2 please thanks
Alex

Answer:

c) 2x+1

Step-by-step explanation:

Let's x be number of Nick's goals.

Emma has scored 1 more than twice the number of Nicks.

1 more is +1, of twices the number is 2x.

so 2x+1=15

6 0
3 years ago
Read 2 more answers
Italian delight sells three sizes of pizzas at different prices. If you buy all three, it costs a total of $46.24. A medium pizz
beks73 [17]

Answer:

$12.99

Step-by-step explanation:

This is because 15.75+17.5= 33.25. 46.24-33.25= 12.99 and therefore, a small pizza should cost 12.99.

4 0
4 years ago
How do you do this? I’m really lost
Katen [24]

Answer:


Step-by-step explanation:

To do these the main think to consider is the boundaries of the functions.  In other words, check when the boundary is true and use that function.  And so,

If we look at 1a.) f(-3) this means that x=-3.  Now check the boundary condition of both equations first.  For 6x-1 use it only if x<0 well is -3<0? Yes, so we will use this function.  But let's check why we won't use 7x+3 this is because the boundary is x≥0 and since x=-3, -3≥0 is false so we dont use that function.  Therefore:

f(x)=6x-1

f(-3)= 6(-3) - 1 = -18 - 1 = -19

1b.) Same idea so we will use 7x+3 because 0≥0 is true and so:

f(x)= 7x + 3

f(0) = 7(0) + 3 = 0 + 3 = 3

1c.) We will use the second equation since 4≥0 is true and so:

f(x) = 7x + 3

f(4) = 7(4) + 3 = 28 + 3 = 31


You will use the same logic to solve 2 and 3.  Good luck! Hope this helps!

6 0
3 years ago
Help me i'll give brainlist
Levart [38]

Answer:

x=\frac{1}{2}

Step-by-step explanation:

equation of a circle:  (x - h)^2+(y-k)^2=r^2

where (h, k) = center and r = radius

From inspection, we can see that the center of the circle = (0, 0)

and the radius = 1

\implies (x - 0)^2+(y-0)^2=1^2

\implies x^2+y^2=1

Substitute y=\frac{\sqrt{3}}{2}  into  x^2+y^2=1  and solve for x:

\implies x^2+(\frac{\sqrt{3}}{2})^2=1

\implies x^2+\frac{3}{4}=1

\implies x^2=\frac{1}{4}

\implies x=\pm \sqrt{\frac{1}{4}}

\implies x=\pm\frac{1}{2}

As point P is in quadrant 1, x is positive, so x=\frac{1}{2}

7 0
2 years ago
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