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3 years ago

The full question is in the picture, please answer <33

Mathematics

1 answer:

EastWind [94]3 years ago

3 0

Hello! Sauce B and C do not have he highest numbers and they were not any of the highest rated sauces. Therefore, A and B are eliminated. Sauce D was rated 4 in terms of cost, making it the best price and Sauce C has a score of 1, making it the worst price. Sauce D would be good to buy it cost was a big concern, but it was rated 2nd in the family anyways, so it would be fine for them. The answer is C.

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Olivia decides to hire an electrician. The electrician charges $35 to come out to Olivia's

atroni [7]

Answer:

Step-by-step explanation:

Total cost

C (x) = 35+ 60x

Where,

Fixed cost= $35

Variable cost = 60x

x= number of hours of work

Total cost is the addition of fixed and variable cost

C (x) = 35+ 60x

C(5)= 35 + 60(5)

= 35 + 300

=335

C(5) = 335

C(5) = 335 is Olivia's total cost of hiring the electrician

x=5 is the electrician's number of hours of work

35= fixed cost of hiring the electrician

60(5) = 300 is the variable cost of hiring the electrician for 5 hours

5 0

3 years ago

Mia had $32. Then she started to receive $5 a week as an allowance. She plans to save all of her money for a bicycle and draws a

kykrilka [37]

(4,52) would be the ordered pairs.

Hope that helped :)

5 0

3 years ago

Need help on these math questions. please and thank u

Svetach [21]

9514 1404 393

Answer:

a) x = -3

b) y = (28/27)x -27

Step-by-step explanation:

a) College street has a slope of 0, so is a horizontal line. 2nd Ave is perpendicular, so is a vertical line, described by an equation of the form ...

x = constant

For 2nd Ave to intersect the point (-3, 1), the constant must match that x-coordinate. The equation is ...

x = -3

b) Since Ace Rd is perpendicular to Davidson St, its slope will be the opposite reciprocal of the slope of Davidson St. The slope of Ace Rd is ...

m = -1/(-27/28) = 28/27

Using the point-slope equation for a line, we can model Ace Rd as ...

y -y1 = m(x -x1)

y -1 = (28/27)(x -27)

y = (28/27)x -27

4 0

3 years ago

Let C(n, k) = the number of k-membered subsets of an n-membered set. Find (a) C(6, k) for k = 0,1,2,...,6 (b) C(7, k) for k = 0,

vladimir1956 [14]

Answer:

(a) $C(6,0) = 1$ , $C(6,1) = 6$ , $C(6,2) = 15$ , $C(6,3) = 20$ , $C(6,4) = 15$ , $C(6,5) = 6$ , $C(6,6) = 1$ .

(b) $C(7,0) = 1$ , $C(7,1) = 7$ , $C(7,2) = 21$ , $C(7,3) = 35$ , $C(7,4) = 35$ , $C(7,5) = 21$ , $C(7,6) = 7$ , $C(7,7)=1$ .

Step-by-step explanation:

In this exercise we only need to recall the formula for C(n,k):

$C(n,k) = \frac{n!}{k!(n-k)!}$

where the symbol $n!$ is the factorial and means

$n! = 1\cdot 2\cdot 3\cdot 4\cdtos (n-1)\cdot n$ .

By convention 0!=1. The most important property of the factorial is $n!=(n-1)!\cdot n$ , for example 3!=1*2*3=6.

(a) The explanations to the solutions is just the calculations.

$C(6,0) = \frac{6!}{0!(6-0)!} = \frac{6!}{6!} = 1$

$C(6,1) = \frac{6!}{1!(6-1)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,2) = \frac{6!}{2!(6-2)!} = \frac{6!}{2\cdot 4!} = \frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,3) = \frac{6!}{3!(6-3)!} = \frac{6!}{3!\cdot 3!} = \frac{5!\cdot 6}{6\cdot 6} = \frac{5!}{6} = \frac{120}{6} = 20$

$C(6,4) = \frac{6!}{4!(6-4)!} = \frac{6!}{4!\cdot 2!} = frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,5) = \frac{6!}{5!(6-5)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,6) = \frac{6!}{6!(6-6)!} = \frac{6!}{6!} = 1$ .

(b) The explanations to the solutions is just the calculations.

$C(7,0) = \frac{7!}{0!(7-0)!} = \frac{7!}{7!} = 1$

$C(7,1) = \frac{7!}{1!(7-1)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7$

$C(7,2) = \frac{7!}{2!(7-2)!} = \frac{7!}{2\cdot 5!} = \frac{6!\cdot 7}{2\cdot 5!} = \frac{5!\cdot 6\cdot 7}{2\cdot 5!} = \frac{6\cdot 7}{2} = 21$

$C(7,3) = \frac{7!}{3!(7-3)!} = \frac{7!}{3!\cdot 4!} = \frac{6!\cdot 7}{6\cdot 4!} = \frac{5!\cdot 6\cdot 7}{6\cdot 4!} = \frac{120\cdot 7}{24} = 35$