<span>The probability that a house in an urban area will develop a leak is 55%. if 20 houses are randomly selected, what is the probability that none of the houses will develop a leak? round to the nearest thousandth.
Use binomial distribution, since probability of developing a leak, p=0.55 is assumed constant, and
n=20, x=0
and assuming leaks are developed independently between houses,
P(X=x)
=C(n,0)p^x* (1-p)^(n-x)
=C(20,0)0.55^0 * (0.45^20)
=1*1*0.45^20
=1.159*10^(-7)
=0.000
</span>
Answer:
-3/4
Step-by-step explanation:
-5/4 + 2/4 = -3/4
Hope this helps :)
Answer:
n = 18
Step-by-step explanation:
2n - 5 = 31
Add 5 to each side
2n - 5+5 = 31+5
2n = 36
Divide each side by 2
2n/2 = 36/2
n = 18
Answer:
I'd need to see more, but because they are the same number just positive and negative they'd be on opposite ends of zero
