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Marizza181 [45]
3 years ago
7

It is 10PM and you are inside in the middle of a large building. Your cell phone is dead so you cannot use wifi or cell signals

to find your location. Unfortunately, your GPS unit cannot find your location either! This is because:
your GPS unit cannot send signals to the satellite when it cannot reach it by line of sight.

it is nighttime and the GPS does not work without sunlight.

GPS relies on the cellular network to send and receive signals.

your GPS unit cannot receive satellite signals when you are indoors away from windows.
Computers and Technology
1 answer:
kupik [55]3 years ago
4 0

<em>The answer is: your GPS unit cannot send signals to the satellite when it cannot reach it by line of sight. </em>

<em> </em>

<em>GPS signals are based on frequencies that can be blocked by solid objects (like walls and roofs). A GPS device is using a series of satellites to detect and see where it is physically located. These frequencies are sent from these plates (satellites) and we cannot expect it to go through all kinds of barriers. When you use a GPS inside a building, a wide variety of physical barriers and potential interference sources make it difficult for the device to detect your location accurately. </em>

<em> </em>

<em />

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The answer to:

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import java.lang.*;               //for using Math.cos() and Math.sin() and Math.toRadians() funcitons in rotate method

public class PolygonTransform

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  public static double[] copy(double[] array)

  {

      double[] newArray = new double[array.length];

      for(int i=0;i<array.length;i++)

      {

          newArray[i] = array[i];

          return newArray;

      }

  }

  public static void scale(double[]x,double[]y,double alpha)

  {

      for(int i=0;i<x.length;i++)

      {

          x[i] *= alpha;

          y[i] *= alpha;

      }

  }

  public static void translate(double[]x,double[]y,double dx,double dy)

  {

      for(int i=0;i<x.length;i++)

      {

          x[i] += dx;

          y[i] += dy;

      }

  }

  public static void rotate(double[] x, double[]y,double theta)

  {

      double rad = Math.toRadians(theta);

      double temp;

      for(int i=0;i<x.length;i++)

      {

          temp = x[i];                           //For storing temporarily the previous value of x before changing so tha it can be used in changing y

          x[i] = x[i]*Math.cos(rad) - y[i]*Math.sin(rad);

          y[i] = y[i]*Math.cos(rad) + temp*Math.sin(rad);  

      }

  }

  public static void main(String args[])

  {

      //This is just implementing you testcase discripted.

      double[]x = new double[4];

      double[]y = new double[4];

      StdDraw.setScale(-5.0, +5.0);

      x = { 0, 1, 1, 0 };

      y = { 0, 0, 2, 1 };

      double alpha = 2.0;

      StdDraw.setPenColor(StdDraw.RED);

      StdDraw.polygon(x, y);

      scale(x, y, alpha);

      StdDraw.setPenColor(StdDraw.BLUE);

      StdDraw.polygon(x, y);

      // Translates polygon by (2, 1).

      StdDraw.setScale(-5.0, +5.0);

      x = { 0, 1, 1, 0 };

      y = { 0, 0, 2, 1 };

      double dx = 2.0, dy = 1.0;

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      StdDraw.polygon(x, y);

      translate(x, y, dx, dy);

      StdDraw.setPenColor(StdDraw.BLUE);

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      StdDraw.setScale(-5.0, +5.0);

      x = { 0, 1, 1, 0 };

      y = { 0, 0, 2, 1 };

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      StdDraw.setPenColor(StdDraw.RED);

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      rotate(x, y, theta);

      StdDraw.setPenColor(StdDraw.BLUE);

      StdDraw.polygon(x, y);

  }

}

Explanation:

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