____ a shape within a smartart graphic means moving it to a higher level.

Where do you go to create a workbook?

Over [174]

Answer:

The explaination of this question is given below in the explanation section

Explanation:

The following steps are used to create a workbook.

1- Go to start menu and search about EXCEL (application software) and then click on it to open.

If you already opened a EXCEL's workbook, and you want to create a new workbook, then you follow the following steps:

Click the File tab.
Click New.
Under Available Templates, double-click Blank Workbook. Keyboard shortcut To quickly create a new, blank workbook, you can also press CTRL+N.

A new workbook will be created.

6 0

4 years ago

Create a recursive method, a method that calls itself, that returns the number of vowels that appear in any string given. Keep i

kvv77 [185]

<h2>Answer:</h2>

//Define the method as noOfVowels

//Let it receive the string to be checked as argument

public static int noOfVowels(String string){

//Check the length of the string

//If it is less than 1, then it is an empty string

//Hence return 0

if(string.length() < 1){

return 0;

}

//Else,

else{

//get the character at the first position in the string

//and convert it to a lower case

char x = string.toLowerCase().charAt(0);

//Check if the character is a vowel

if (x == 'a' || x == 'e' || x == 'i' || x == 'o' || x == 'u'){

//if it is a vowel, add 1 to a recall of the method.

//But this time, call the method with

//the string excluding the first character.

//i.e the substring of the string starting at index 1 rather than 0

return 1 + noOfVowels(string.substring(1));

}

else {

//If it is not a vowel, just recall the method with

//the string excluding the first character

//i.e the substring of the string starting at index 1 rather than 0

return noOfVowels(string.substring(1));

}

<h2>Explanation:</h2><h2></h2>

The code has been written in Java and it contains comments explaining every part of the code. Please go through the comments carefully.

The actual lines of code have been written in bold face to distinguish them from comments.

The code is re-written without comments as follows;

public static int noOfVowels(String string){

if(string.length() < 1){

return 0;

}

else{

char x = string.toLowerCase().charAt(0);

if (x == 'a' || x == 'e' || x == 'i' || x == 'o' || x == 'u'){

return 1 + noOfVowels(string.substring(1));

}

else{

return noOfVowels(string.substring(1));

}

3 0

3 years ago

Assume that a large number of consecutive IP addresses are available starting at 198.16.0.0 and suppose that two organizations,

Fiesta28 [93]

Answer & Explanation:

An IP version 4 address is of the form w.x.y.z/s

where s = subnet mask

w = first 8 bit field, x = 2nd 8 bit field, y = 3rd 8 bit field, and z = 4th 8 bit field

each field has 256 decimal equivalent. that is

binary denary or decimal

11111111 = 2⁸ = 256

w.x.y.z represents

in binary

11111111.11111111.11111111.11111111

in denary

255.255.255.255

note that 255 = 2⁸ - 1 = no of valid hosts/addresses

there are classes of addresses, that is

class A = w.0.0.0 example 10.0.0.0

class B = w.x.0.0 example 172.16.0.0

class C = w.x.y.0 example 198.16.8.1

where w, x, y, z could take numbers from 1 to 255

Now in the question

we were given the ip address : 198.16.0.0 (class B)

address of quantity 4000, 2000, 8000 is possible with a subnet mask of type

255.255.0.0 (denary) or

11111111.11111111.00000000.00000000(binary) where /s = /16 That is no of 1s

In a VLSM (Variable Length Subnet Mask)

Step 1

we convert the number of host/addresses for company A to binary

4000 = 111110100000 = 12 bit

step 2 (subnet mask)

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11110000.000000 /20

now we have added 4 1s in the 3rd field to reserve 12 0s

subnet mask: 255.255.16.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1  1  1 1 1 1

128 64 32 16 8 4 2 1

step 3

in the ip network address: 198.16.0.0/19 (subnet representation) we increment this using 16

that is 16 is added to the 3rd field as follows

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.0.1 - 198.16.15.255(last valid IP address)

Company B starts+16: 198.16.16.0 - 198.16.31.255

+16: 198.16.32.0- 198.16.47.255 etc

we repeat the steps for other companies as follows

Company B

Step 1

we convert the number of host/addresses for company B to binary

2000 = 11111010000 = 11 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 11 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11111000.000000 /21

now we have added 5 1s in the third field to reserve 11 0s

subnet mask: 255.255.8.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1 1 1  1 1 1

128 64 32 16 8  4 2 1

Step 3

Starting from after the last valid Ip address for company A

in the ip network address: 198.16.16.0/21 (subnet representation) we increment this using 8

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.16.1 - 198.16.23.255(last valid IP address)

Company C starts +16: 198.16.24.0- 198.16.31.255

+16: 198.16.32.0- 198.16.112.255 etc

Company C

Step 1

we convert the number of host/addresses for company C to binary

4000 = 111110100000 = 12 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11110000.000000 /20

now we have added 4 1s in the 3rd field to reserve 12 0s

subnet mask: 255.255.16.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1 1 1 1 1 1

128 64 32 16 8 4 2 1

Step 3

Starting from after the last valid ip address for company B

in the ip network address: 198.16.24.0/20 (subnet representation) we increment this using 16

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.24.1 - 198.16.39.255(last valid IP address)

Company C starts +16: 198.16.40.0- 198.16.55.255

+16: 198.16.56.0- 198.16.71.255 etc

Company D

Step 1

we convert the number of host/addresses for company D to binary

8000 = 1111101000000 = 13 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 13 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11100000.000000 /19

now we have added 3 1s in the 3rd field to reserve 13 0s

subnet mask: 255.255.32.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1  1  1 1 1 1 1

128 64 32  16 8 4 2 1

Step 3

Starting from after the last valid ip address for company C

in the ip network address: 198.16.40.0/20 (subnet representation) we increment this using 32

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.40.1 - 198.16.71.255(last valid IP address)

Company C starts +16: 198.16.72.0- 198.16.103.255

+16: 198.16.104.0- 198.16.136.255 etc

5 0

3 years ago

What is the difference between algorithm and flowchart

Tomtit [17]

Flowchart - diagram created by different shapes to show flow of data
algorithm - step by step procedure to solve the problem

A flowchart is a representation of an algorithm

5 0

3 years ago

Write a piece of code that constructs a jagged two-dimensional array of integers named jagged with five rows and an increasing n

Ksivusya [100]

Answer:

Explanation:

The following code is written in Java and it uses nested for loops to create the array elements and then the same for loops in order to print out the elements in a pyramid-like format as shown in the question. The output of the code can be seen in the attached image below.

class Brainly {

public static void main(String[] args) {

int jagged[][] = new int[5][];

int element = 1;

for(int i=0; i<5; i++){

jagged[i] = new int[i+1]; // creating number of columns based on current value

for(int x = 0; x < jagged[i].length; x++) {

jagged[i][x] = element;

element += 1;

}

System.out.println("Jagged Array elements are: ");

for ( int[] x : jagged) {

for (int y : x) {

System.out.print(y + " ");

}

System.out.println(' ');

}

4 0

3 years ago